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Oksi-84 [34.3K]
4 years ago
8

25 POINTS

Mathematics
1 answer:
AlladinOne [14]4 years ago
6 0

Answer:

<em>False</em>

Step-by-step explanation:

<u>Equations With Absolute Value</u>

The absolute value of any number is defined as

|x|=\left \{ {{x,\ x\geq 0} \atop {-x,\ x< 0}} \right.

To solve any equation where the absolute value bars appear, we must consider both signs of its argument because it can be positive or negative.

The equation is given as

7- |4x+1| =-2

To solve it, we must isolate the absolute value and then (not before), consider both signs for its argument.

The proposed procedure consist in writing the equation as two separate equations:

7-4x+1=-2

7-4x+1=2

which is wrong because we are changing the sign of the right side of the equation without isolating the absolute value. Those equations would lead to inaccurate answers. So the statement is FALSE

The correct procedure is first to isolate the absolute value

7+2 = |4x+1|=9

Now we set

4x+1=9\\or\\4x+1=-9

which lead to the solutions

x = 2, x = - 5/2

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Can someone help me with this?
zaharov [31]

Answer:

1200

Step-by-step explanation:

30 * 40 = 1200

the actual total cost would be 1326 because 39 * 34 = 1326

4 0
3 years ago
Read 2 more answers
Simplify 1/x-3+4/x divided by 4/x-1/x-3
Alchen [17]
The answer is \frac{5x-12}{3x-12}

The expression is: \frac{ \frac{1}{x-3}+ \frac{4}{x}  }{ \frac{4}{x} - \frac{1}{x-3} }

Let's factorize it:
\frac{ \frac{1}{x-3}+ \frac{4}{x}  }{ \frac{4}{x} - \frac{1}{x-3} } = \frac{ \frac{x*1}{x(x-3)}+ \frac{4*(x-3)}{(x-3)*x}}{ \frac{(x-3)*4}{(x-3)*x}- \frac{x*1}{x*(x-3)}}= \frac{ \frac{x+4(x-3)}{x(x-3)} }{ \frac{4(x-3)-x}{x(x-3)} }

Since \frac{ \frac{a}{b} }{ \frac{c}{d} }= \frac{a}{b}/ \frac{c}{d}= \frac{a*d}{b*c}, then:
\frac{ \frac{x+4(x-3)}{x(x-3)} }{ \frac{4(x-3)-x}{x(x-3)} }= \frac{(x+4(x-3))*x(x-3)}{(4(x-3)-x)*x(x-3)}

Cancel x(x-3) and simplify:
\frac{(x+4(x-3))*x(x-3)}{(4(x-3)-x)*x(x-3)} = \frac{x+4(x-3)}{4(x-3)-x} = \frac{x+4x-12}{4x-12 -x} = \frac{5x-12}{3x-12}
4 0
3 years ago
HELP!
Tju [1.3M]

Answer:

  (b) 7.28 cis(105.945°)

Step-by-step explanation:

The trig form of a vector is always ...

  magnitude(cos(angle)·i +sin(angle)·j)

Sometimes, that is abbreviated ...

  magnitude cis(angle)  or  magnitude∠angle

where the "angle" is measured counterclockwise from the +x axis.

__

The forms showin in choices C and D can be rejected immediately because the sine and cosine coefficients are incorrectly placed. To differentiate between choices A and B, you need to know whether the angle is greater than 90°. The terminal point is above and left of the initial point, so the angle must be <em>more than 90°</em>. (It can help to plot the points on a graph.)

  u = 7.28(cos 105.945°i + sin 105.945°j)

8 0
2 years ago
The perimeter of a rectangle is 24 in. and its length l l is 3 times the width w w . what is the length and width \left(l,w\righ
patriot [66]
Since p=24 and to get p you do 3w+3w+w+w which equals 8w=24 and 24/8 is 3 so your answer is 3
8 0
4 years ago
If m and n are real numbers such that 4m + n = 10, then which of the following expressions represents m?
dalvyx [7]
4m + n = 10

4m = -n + 10

m = \dfrac{-n + 10}{4}

or

m = \dfrac{10 - n}{4}
4 0
4 years ago
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