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Eva8 [605]
3 years ago
5

Pythagoras Theorem and Quadratic Equations Solve for x: a= (x-2) b= 9 c= (x+1)

Mathematics
2 answers:
UkoKoshka [18]3 years ago
6 0

Answer:

x = -13

Step-by-step explanation:

using Pythagoras theorem which says that the square of the hyponeneus side of a right angled triangle is equal to the sum of square of the two opposite sides.

mathematically,

|H|² = |OPP|² + |ADJ|²

H= (x-2) , opp= 9 adj=(x+1)

(x-2)² = (9)² + (x+1)²

x² -4x + 4 = 81 + x²+2x+1

collecting the like terms

x²- x² - 4x-2x = 81 +1 - 4

- 6x = 89 -4

-6x = 78

divide both sides by the coefficient of x which is -6

-6x/-6 = 78/-6

x = -13

Alex_Xolod [135]3 years ago
3 0

Answer:

Step-by-step explanation:

Pythagoras theorem

a^2=b^2+c^2

(x-2)^2=9^2+(x+1)^2

x^2-4x+4=81+x^2+2x+1

Collect like terms

-4x-2x=82-4

-6x=78

x=-13

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Hi could some PLEASE help me !!!!
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Answer:

3x=78+x-2

Step-by-step explanation:

3 0
3 years ago
Find all two digit positive integers in which the difference between the integer and the product of its two digits is 12
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Let ab be a 2 digit number, then ab=10a+b, where a and b are digits, a≠0.

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10a+b(1-a)=12

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so the solutions (a, b) are (2, 8) and (3, 9)


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