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ruslelena [56]
3 years ago
14

A cylindrical potato chip container has a diameter of 3.5 inches and a height of 12 inches. What is the volume of the chip conta

iner? Use 3.14 for pi. Round your answer to the nearest hundredth.
57.73 in3
115.40 in3
350.65 in3
461.81 in3
Mathematics
1 answer:
Leni [432]3 years ago
8 0

Answer:

V  =  38.47 in^3

Step-by-step explanation:

The container base radius is half the diameter, that is, 1.75 in, and the height is 12 in.  The formula for the volume of a cylinder of radius r and height h is V = (1/3)(pi)(r)^2h, which in this particular case comes out to:

V = (1/3)(3.14)(1.75 in)^2*(12 in), or

V  =  38.47 in^3

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a 15-foot telephone pole has a wire that extends from the top of the pole to the ground. The wire and the ground form a 42 degre
scoundrel [369]

Answer:

The length of the wire is 22.42 feet

The distance from the base of the pole to the spot where the wire touches the ground is 16.66 feet

Step-by-step explanation:

* Lets explain the situation in the problem

- The telephone pole , the wire and the ground formed a right triangle

- The wire is the hypotenuse of the triangle

- The height of the telephone pole and the distance from the base of

 the pole to the spot where the wire touches the ground are the legs

 of the triangle

- The angle between the wire and the ground is 42°

- The angle 42° is opposite to the height of the telephone pole

- The height of the telephone pole is 15 feet

* Lets use the trigonometry functions to find the length of the wire

 (hypotenuse) and the distance from the base of the pole to the spot

 where the wire touches the ground

∵ sin Ф = opposite/hypotenuse

∵ Ф = 42° and its opposite side = 15 feet

∴ sin 42 = 15/hypotenuse ⇒ by using cross multiplication

∴ sin 42° (hypotenuse) = 15 ⇒ divide both sides by sin 42

∴ hypotenuse = 15/sin 42° = 22.42 feet

∵ The length of the wire is the hypotenuse

∴ The length of the wire is 22.42 feet

∵ The distance from the base of the pole to the spot where the wire

   touches the ground is the adjacent side to the angle 42°

∵ tan Ф = opposite/adjacent

∴ tan 42° = 15/adjacent ⇒ by using cross multiplication

∴ tan 42° (adjacent) = 15 ⇒ divide both sides by sin 42

∴ adjacent = 15/tan 42° = 16.66 feet

∵ The adjacent side is the distance from the base of the pole to the

  spot where the wire touches the ground

∴ The distance from the base of the pole to the spot where the wire

   touches the ground is 16.66 feet

7 0
4 years ago
A colony of bacteria is growing exponentially according to the function below, where t is in hours. How many bacteria are there
pychu [463]
The growth of the bacteria is expressed as:

<span>B(t) = 4 e^0.8t
</span>
where t is the time in units of hours. If the bacteria is allowed to grow for 8 hours then the number of bacteria present would be,


<span>B(t) = 4 e^0.8(8)
</span><span>B(t) = 2407</span>
5 0
3 years ago
Read 2 more answers
18 p <br>please help me!
nevsk [136]
It should be the second one
7 0
3 years ago
Awnser choices <br><br> a-360<br> b- 9<br> c-10<br> d-180
cluponka [151]

Answer:

C- 10

Step-by-step explanation:

2x + 160 = 180 \\ 2x = 180 - 160 \\ 2x = 20 \\ x = 20 \div 2 \\ x = 10

7 0
3 years ago
Read 2 more answers
An elliptical-shaped path surrounds a garden, modeled by quantity x minus 20 end quantity squared over 169 plus quantity y minus
Margaret [11]

The <em>maximum</em> distance between any two points of the ellipse is 34 feet.

<h3>Procedure - Determination of the distance between two points of a ellipse</h3>

The maximum distance between any two points of a ellipse is the <em>maximum</em> distance between the ends of the ellipse along the <em>longest</em> axis, which is parallel to the y-axis in this case.

In addition, the equation of the ellipse in <em>standard</em> form is defined by this formula:

\frac{(x-h)^{2}}{a^{2}} + \frac{(y-k)^{2}}{b^{2}} = 1 (1)

Where:

  • h, k - Coordinates of the center of the ellipse.
  • a, b - Lengths of each semiaxis.

Hence, the maximum distance (d_{max}), in feet, is calculated by this formula:

d_{max} = 2\cdot b (2)

If we know that b = 17, then the maximum distance between any two points of the ellipse is:

d_{max} = 2\cdot (17\,ft)

d_{max} = 34\,ft

The <em>maximum</em> distance between any two points of the ellipse is 34 feet. \blacksquare

<h3>Remark</h3>

The statement is incomplete and poorly formatted, correct form is presented below:

<em>An elliptical-shaped path surrounds a garden, modeled by </em>\frac{(x-20)^{2}}{169} + \frac{(y-18)^{2}}{289} = 1<em>, where all measurements are in feet. What is the maximum distance between any two points of the path.</em>

To learn more on ellipses, we kindly invite to check this verified question: brainly.com/question/19507943

5 0
2 years ago
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