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3 years ago

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A loan company charged 35 percent interest on every dollar borrowed. If a person borrowed 177 dollars, how much would they end u

p paying total?

1 answer:

pav-90 [236]3 years ago

8 0

We know that 35 percent interest is applied on every dollar borrowed.
thus, for 1 dollor borrowed. the interest would be 0.35 dollar.
for 177 dollars, the interest would be 0.35*177.
plus the original 177 dollar, they would end up paying 177+0.35*177=238.95.

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Prove the following DeMorgan's laws: if LaTeX: XX, LaTeX: AA and LaTeX: BB are sets and LaTeX: \{A_i: i\in I\} {Ai:i∈I} is a fam

MariettaO [177]

$X-(A\cup B)=(X-A)\cap(X-B)$

I'll assume the usual definition of set difference, $X-A=\{x\in X,x\not\in A\}$ .

Let $x\in X-(A\cup B)$ . Then $x\in X$ and $x\not\in(A\cup B)$ . If $x\not\in(A\cup B)$ , then $x\not\in A$ and $x\not\in B$ . This means $x\in X,x\not\in A$ and $x\in X,x\not\in B$ , so it follows that $x\in(X-A)\cap(X-B)$ . Hence $X-(A\cup B)\subset(X-A)\cap(X-B)$ .

Now let $x\in(X-A)\cap(X-B)$ . Then $x\in X-A$ and $x\in X-B$ . By definition of set difference, $x\in X,x\not\in A$ and $x\in X,x\not\in B$ . Since $x\not A,x\not\in B$ , we have $x\not\in(A\cup B)$ , and so $x\in X-(A\cup B)$ . Hence $(X-A)\cap(X-B)\subset X-(A\cup B)$ .

The two sets are subsets of one another, so they must be equal.

$X-\left(\bigcup\limits_{i\in I}A_i\right)=\bigcap\limits_{i\in I}(X-A_i)$

The proof of this is the same as above, you just have to indicate that membership, of lack thereof, holds for all indices $i\in I$ .

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3 years ago

The function C(x)=−20x+1681 represents the cost to produce x items. What is the least number of items that can be produced so th

Reptile [31]

Answer:

<em>The least number of items to produce is 41</em>

Step-by-step explanation:

<u>Average Cost</u>

Given C(x) as the cost function to produce x items. The average cost is:

$\displaystyle \bar C(X)=\frac{C(x)}{x}$

The cost function is:

$C(x) = -20x+1681$

And the average cost function is:

$\displaystyle \bar C(X)=\frac{-20x+1681}{x}$

We are required to find the least number of items that can be produced so the average cost is less or equal to $21.

We set the inequality:

$\displaystyle \frac{-20x+1681}{x}\le 21$

Multiplying by x:

$-20x+1681 \le 21x$

Note we multiplied by x and did not flip the inequality sign because its value cannot be negative.

Adding 20x:

$1681 \le 21x+20x$

$1681 \le 41x$

Swapping sides and changing the sign:

$41x \ge 1681$

Dividing by 41:

$x\ge 41$

The least number of items to produce is 41

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3 years ago

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Alja [10]

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3 years ago

It takes Bobby 12 hours longer to build a robot than it takes Alex. Together, they can build the Robot in 8 hours. How long does

anyanavicka [17]

Answer:

24 hours

Step-by-step explanation:

The computation of the number of hours taken by Bobby to build the robot by himself is shown below:

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the number of hours taken by Bobby to build the robot by himself is

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3 years ago