2 years ago

Will give brainliest!!!!Explain how solving -7y > 161 is different from solving 7y > -161.

1 answer:

5 0

To solve -7y > 161, we divide both sides by -7 and we get y < -23. The inequality sign flipped because we divided both sides by a negative number.

To solve 7y > -161, we divide both sides by 7 and it leads to y > -23. The inequality sign does not flip in this case, because we are not dividing both sides by a negative number.

The similarities is that we end up with -23 on the right side, but the inequality signs are different.

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Ivenika [448]

Answer:

Step-by-step explanation:

Hope I was able to help!! :)

7 0

3 years ago

a(t)=(t−k)(t−3)(t−6)(t+3) is a polynomial function of tt, where kk is a constant. Given that a(2)=0a(2)=0, what is the absolute

Crank

Since $a(2)=0$ , we know that $t-2$ must be a factor of $a(t)$ , so $k=2$ . Then the zeros of $a(t)$ are $t=2,3,6,-3$ , and their product is -108, whose absolute value is 108.