Answer:
im confused
Step-by-step explanation:
Answer:
18cm
Step-by-step explanation:
We have the length of the rectangle but we need to find the width which we'll call w. Area is a, l is length.
a = l * w
20 = 5 * w
divide both sides by 5 to cancel the multiplication by 5 on the right side
4 = w
The rectangle is going to have two sides that are the length of l, and two sides that are the the length of w. We're looking for the perimiter p.
p = 2l + 2w
p = (2 * 5) + (2 * 4)
p = 18
Answer:
A and B is correct ...............
Answer:
The answer is below
Step-by-step explanation:
Let us assume that the length of the square be x. Therefore the area of the square is given as:
Area of square = length × length = x × x = x²
Given that the length of one side of the rectangle is twice the length of the other side. Let the length of the small side be a therefore the length of the long side = 2a
The area of the rectangle = length of small side × length of long side = a × 2a = 2a²
Since both the rectangle and square are to occupy the same space, hence:
Length of small side = a = 
, length of long side = 2a = 
The length of the sides are length of the square side divide by √2 () and twice the length of the square side divide by √2 ()
Let a = Adult tickets, s = Student tickets; we are going to set up a system of equations.
8a + 4s = 880
a - s = 20
We are going to multiply the second equation by so that we can cancel out one of the variables and solve for the other. This gives you:
8a + 4s = 880
4a - 4s = 20
Notice the s-variables will cancel:
12a = 900
a = 75
Now we plug in the amount of adult tickets to solve for the student ones.
75 - s = 20
- s = - 55
Divide both sides by - 1
s = 55.
There were 55 student tickets sold and 75 adult tickets.
