Let
. Then
and
are two fundamental, linearly independent solution that satisfy
Note that
, so that
. Adding
doesn't change this, since
.
So if we suppose
then substituting
would give
To make sure everything cancels out, multiply the second degree term by
, so that
Then if
, we get
as desired. So one possible ODE would be
(See "Euler-Cauchy equation" for more info)
Hint : The product of the slopes of two lines perpendicular to each other is - 1 .
______________________________
In slope-intercept ( y = ax + b ) from of the linear equations the coefficient of x is the slope of the line.
Thus :
Slope of line a = - 14
______________________________
Suppose that the slope of line b is x according to the Hint we have :
- 14 × x = - 1
negatives simplify
14x = 1
Divide both side by 14
14x ÷ 14 = 1 ÷ 14
x = 1/14
So the slope of line b is 1/14
_____________________________
Now let's find the equation of line b by point-slope formula using the point question have us ( 2 , 6 ) :
y - y( given point ) = Slope × ( x - x ( g p ) )
y - 6 = 1/14 × ( x - 2 )
y - 6 = 1/14 x - 2/14
y - 6 = 1/14 x - 1/7
Add both sides 6
y - 6 + 6 = 1/14 x - 1/7 + 6
y = 1/14 x - 1/7 + 42/7
y = 1/14 x + 41/7
And we're done ...
bro idk tbh... I hope an expert sees this and is able to help you out but I cannot process this
Hello,
"perpendicular to the line y= - 1/2x +4 "
so y = -1/2x + p
-1/2 × 6 + p = 4 ⇔ -3 + p = 4 ⇔ p = 4 + 3 = 7
y = -1/2x + 7
Answer:323/1000
Step-by-step explanation:
