Answer:
HCOOH(aq) + OH-(aq) —> HCOO-(aq) + H2O(l)
Explanation:
HCOOH is a weak acid and so will not ionised completely in solution.
KOH is a strong base and will ionised completely as shown below
KOH(aq) –> K+(aq) + OH-(aq)
The overall reaction can be written as follow:
HCOOH(aq) + K+(aq) + OH-(aq) —> HCOO-(aq) + K+(aq) + H2O(l)
Cancel out the K+ to obtain the net ionic equation as shown below
HCOOH(aq) + OH-(aq) —> HCOO-(aq) + H2O(l)
120 Fahrenheit -32 x 5/9 +273.15 = 322
<u>Answer:</u> The percent composition of fluorene is 33.08 % and benzoic acid is 36.03 %.
<u>Explanation:</u>
We are given:
Mass of mixture = 544 mg
Mass of fluorene after purification = 
Mass of benzoic acid after purification = 196 mg
To calculate the percentage composition of a substance in a mixture, we use the equation:
<u>For fluorene:</u>
Hence, the percent composition of fluorene is 33.08 %
<u>For benzoic acid:</u>
Hence, the percent composition of benzoic acid is 36.03 %
Answer:
A dono wat is da anser sori man hehe
Answer : The correct answer is, Halide hydrocarbon.
Explanation :
Freon : Freon are the simple aliphatic organic compounds which may contains fluorine, carbon, hydrogen, chlorine or bromine. So, they are a type of chlorofluoro carbons (CFCs).
They are considered as refrigerants which are used in air-conditioning and refrigeration system.
