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3 years ago

Identify one type of noncovalent bond present in each solid.

Chemistry

1 answer:

NeX [460]3 years ago

7 0

Answer:

Explanation:

The question is not complete, the cmplete question is:

Identify one type of noncovalent bond present in each solid.

1) Table salt (NaCl) 2) Graphite (repeating)

a. hydrogen bonds

b. ionic interactions

c. van der Waals interactions

d. hydrophobic interactions

Answer:

1) Table salt

b. ionic interactions

Ionic bond are formed between atoms with incomplete outermost shell. Some atoms add electrons to their outermost shell to make the shell complete hence making it a negative ion while some atoms loses their electron to make the outermost shell complete becoming a positive ion. In NaCl, sodium (Na) has 1 electron in its outermost shell which it transfers to Cl which has 7 electrons in the outermost shell. Hence after the bonding the outermost shell of the atoms become complete.

2) Graphite

c. Van Der Waals interaction

Van der waal forces are weak interaction between molecules that exist between close atoms. Carbon atoms in graphite planes have covalent bond, these graphite planes are known as graphenes. Bonds between graphenes are very weak and are van der waals forces.

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Nadusha1986 [10]

Answer:

1 electron

Explanation:

These metals have a single electron in the outer shell

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3 years ago

Calculate Kc for the reaction: 2 HI(g) ⇄ H2(g) + I2(g) given that the concentrations of each species at equilibrium are as follo

Paul [167]

Answer: The value of $K_c$ for the given reaction is 0.224

Explanation:

For the given chemical equation:

$2HI(g)\rightleftharpoons H_2(g)+I_2(g)$

The expression of $K_c$ for given equation follows:

$K_c=\frac{[H_2][I_2]}{[HI]^2}$

We are given:

$[HI]_{eq}=0.85M$

$[H_2]_{eq}=0.27M$

$[I_2]_{eq}=0.60M$

Putting values in above expression, we get:

$K_c=\frac{0.27\times 0.60}{(0.85)^2}=0.224$

Hence, the value of $K_c$ for the given reaction is 0.224

4 0

4 years ago

if callie has 1,012 beads. and she wants to divide the beads evenly to make 22 necklaces. how many beads will be used for each n

borishaifa [10]

1012/22 = 46

46 beads will be used in each necklace

hope this helps

7 0

4 years ago

Read 2 more answers

For the following reaction, 5.20 grams of propane (C3H8) are allowed to react with 22.5 grams of oxygen gas. propane (C3H8) (g)

Sliva [168]

Answer:

15.58g of CO₂ is the maximum amount that can be produced

Explanation:

The propane reacts with oxygen as follows:

C₃H₈ + 5O₂ → 3CO₂ + 4H₂O

Where 1 mole of propane reacts with 5 moles of oxygen

To solve this question we need to find the moles of propane and oxygen to find limiting reactant using the chemical reaction:

Moles propane -Molar mass: 44.1g/mol-:

5.20g * (1mol / 44.1g) = 0.118 moles

Moles oxygen -Molar mass: 32g/mol-:

22.5g O₂ * (1mol / 32g) = 0.703 moles

For a complete reaction of 0.703 moles of oxygen are:

0.703 moles O₂ * (1mol C₃H₈ / 5mol O₂) = 0.141 moles of propane are necessaries. As there are just 0.118 moles of propane, propane is limiting reactant.

The moles of carbon dioxide that are produced are:

0.118 moles C₃H₈ * (3 moles CO₂ / 1 mol C₃H₈) = 0.354 moles CO₂

The maximum mass that can be produced is -Molar mass CO₂: 44.01g/mol-:

0.354 moles CO₂ * (44.01g / mol) =

15.58g of CO₂ is the maximum amount that can be produced

4 0

3 years ago

When a chemical reaction occurs, what always stays the same between reactants and products?

BlackZzzverrR [31]

The total number of atoms remains unchanged, always. But the chemical properties change :)

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3 years ago