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Korvikt [17]
3 years ago
12

How many significant figures are in this number? 3x10^6 If it's right 30 POINTS !!!!!!!

Chemistry
1 answer:
DENIUS [597]3 years ago
8 0
There is 1 significant figure in this number
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The test tube that contained the calcium metal was probably the most difficult of the test tubes to clean. Why was aqueous HCl u
natita [175]

Answer:

The HCl will dissolve the calcium readily

Explanation:

HCl will react with d calcium, dissolving it to produce Hydrogen gas

6 0
3 years ago
When 80.0 mL of a 0.812 M barium chloride solution is combined with 40 mL of a 1.52 M potassium sulfate solution, 10.8 g of bari
BabaBlast [244]

Answer:

76.1%

Explanation:

The reaction that takes place is:

  • BaCl₂ + K₂SO₄ → BaSO₄ + 2KCl

First we determine how many moles of each reactant were added:

  • BaCl₂ ⇒ 80 mL * 0.812 M = 64.96 mmol BaCl₂
  • K₂SO₄ ⇒ 40 mL * 1.52 M = 60.8 mmol K₂SO₄

Thus K₂SO₄ is the limiting reactant.

Using the <em>moles of the limiting reactant</em> we <u>calculate how many moles of BaSO₄ would have been produced if the % yield was 100%</u>:

  • 60.8 mmol K₂SO₄ * \frac{1mmolBaSO_4}{1mmolK_2SO_4} = 60.8 mmol BaSO₄

Then we <u>convert that theoretical amount into grams</u>, using the <em>molar mass of BaSO₄</em>:

  • 60.8 mmol BaSO₄ * 233.38 mg/mmol = 14189.504 mg BaSO₄
  • 14189.504 mg BaSO₄ / 1000 = 14.2 g BaSO₄

Finally we calculate the % yield:

  • % yield = 10.8 g / 14.2 g * 100 %
  • % yield = 76.1%
7 0
3 years ago
The ability of a substance to combine chemically with another substance.
Marysya12 [62]
Reactivity. It is the ability of matter to combine chemically with other substances.
8 0
2 years ago
A chemist makes of nickel(II) chloride working solution by adding distilled water to of a stock solution of nickel(II) chloride
Lady_Fox [76]

Answer:

0.0900 mol/L

Explanation:

<em>A chemist makes 330. mL of nickel(II) chloride working solution by adding distilled water to 220. mL of a 0.135 mol/L stock solution of nickel(II) chloride in water. Calculate the concentration of the chemist's working solution. Round your answer to significant digits.</em>

Step 1: Given data

  • Initial concentration (C₁): 0.135 mol/L
  • Initial volume (V₁): 220. mL
  • Final concentration (C₂): ?
  • Final volume (V₂): 330. mL

Step 2: Calculate the concentration of the final solution

We prepare a dilute solution from a concentrated one. We can calculate the concentration of the working solution using the dilution rule.

C₁ × V₁ = C₂ × V₂

C₂ = C₁ × V₁/V₂

C₂ = 0.135 mol/L × 220. mL/330. mL = 0.0900 mol/L

3 0
3 years ago
Identify the precipitate (if any) that forms when KOH and Cu(NO3)2 are mixed
Art [367]
Cu(OH)2 is the precipitate that forms
6 0
3 years ago
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