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svetlana [45]
3 years ago
6

IMPORTANT. LOTS OF POINTS. SOLVE NOW. Rays OM , ON , and OP coincide at time t=0. At the same instant in time, OM and OP begin t

o rotate in the plane about point O, but in opposite directions. Ray ON remains fixed. Ray OM rotates at a constant rate of 3° per second with respect to ON , while OP rotates at a constant rate of 6° per second. What is the smallest positive value of t, in seconds, in which rays OM and OP will coincide again? When t=30 min, how many more revolutions has ray OP completed than ray OM ?
Mathematics
2 answers:
AURORKA [14]3 years ago
8 0

Answer:

t=40 seg OP does 15 more revolutions than OM

Step-by-step explanation:

i didn't do this, just answering it just in case someone doesnt look at the comments

Anton [14]3 years ago
6 0
I believe if Socratic is right the answer is -x+4y=8
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