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2 years ago

FIND XPleasee help mee

Mathematics

1 answer:

makkiz [27]2 years ago

8 0

A. x= 6, -1. B. 1, -7

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How do I find the diameter and circumference when given the area?

JulijaS [17]

Hello from MrBillDoesMath!

Answer:

Diameter = 2r = 2 (sqrt(24/Pi))

Circumference = 4 sqrt(6Pi)

Discussion:

Given:

Area of circle = Pi r^2

24 = Pi r^2 => (as Pi r^2 is the formula for area of a circle)

24/Pi = r^2 => ( now take the square root of both sides)

r= sqrt(24/Pi)

Diameter = 2r = 2 (sqrt(24/Pi))

Circumference = 2 PI r = 2Pi (sqrt(24/Pi))

= 2Pi (sqrt(24)/sqrt(Pi) )

= 2Pi (2sqrt(6)/sqrt(Pi) )

= 4 (pi/ sqrt(Pi) ) sqrt(6)

= 4 sqrt(Pi) sqrt(6)

= 4 sqrt(6Pi)

Thank you,

MrB

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2 years ago

What is the radius for the circle given by the equation?

alisha [4.7K]

Use:

$(a-b)^2=a^2-2ab+b^2\qquad(*)$

$x^2+y^2-6y-12=0\ \ \ \ |+12\\\\x^2+y^2-6y=12\\\\x^2+y^2-2y\cdot3=12\ \ \ \ |+3^2\\\\x^2+\underbrace{y^2-2\cdot y\cdot3+3^2}_{(*)}=12+3^2\\\\x^2+(y-3)^2=21\\\\\boxed{k=3}$

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2 years ago

If a-1/a=4 then find a^2-1/a^2

Pavel [41]

Answer:

This is the ever best answer. All the best

5 0

2 years ago

Need help with number 3 inequalities with variables on both sides

Volgvan

Answer:

x ≤ 2

Step-by-step explanation:

We are given the inequality:

$\displaystyle{2x-3 \leq \dfrac{x}{2}}$

First, get rid of the denominator by multiplying both sides by 2:

$\displaystyle{2x\cdot 2-3\cdot 2 \leq \dfrac{x}{2}\cdot 2}\\\\\displaystyle{4x-6 \leq x}$

Add both sides by 6 then subtract both sides by x:

$\displaystyle{4x-6+6 \leq x+6}\\\\\displaystyle{4x \leq x+6}\\\\\displaystyle{4x-x \leq x+6-x}\\\\\displaystyle{4x-x \leq 6}\\\\\displaystyle{3x \leq 6}$