Sample space={A,R,I,T,H,M,E,T,I,C}
1ST (Choosing T) ==> P(1st draw) = 2/10 = 1/5 = 0.2
2ND (Choosing again a T) ==> P(2nd draw) = 1/9 = 0.11
Since it's a conditional probability then P (1st T AND 2nd T) = 0.2 x 0.11 =0.022
Answer:
C
Step-by-step explanation:
506 x - 92 y + 90 = 498 - 4 x + 6 y
Geometric figure:
line
y = (255 x)/49 - 204/49
510 x - 98 y - 408 = 0
506 x - 92 y + 90 = 6 (y + 83) - 4 x
Real solution:
y = (255 x)/49 - 204/49
Solution:
y = (255 x)/49 - 204/49
Integer solution:
x = 49 n + 40, y = 255 n + 204, n element Z
Solution for the variable y:
y = 51/49 (5 x - 4)
Answer:
$127.80
Step-by-step explanation:
Please let me know if you want me to add an explanation as to why this is the answer. I can definitely do that, I just wouldn’t want to write it if you don’t want me to :)