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4 years ago

20/10 as a mixed number

2 answers:

6 0

First, decide how many times 10 can go into 20. 10 can "fit in" to 20 exactly 2 times. Since there is nothing left over, the "mixed number" is simply 2.
Another way to do this is to just divide the top by bottom, since it will divide evenly.
20/10 = 2.
Answer: 2
Hope that helps!!

Minchanka [31]4 years ago

3 0

20/10 as a mixed number:

20 ÷ 10 = 2.

10 goes into 20 two times. So 20/10 as a mixed number is a whole number: 2.

20/10 = 2

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Solve 12^x^2+5x-4 = 12^2x+6

faust18 [17]

The solutions for ‘x’ are 2 and -5

Step-by-step explanation:

Given equation:

$12^{x^{2}+5 x-4}=12^{2 x+6}$

Since the base on both sides as ‘12’ are the same, we can write it as

$x^{2}+5 x-4=2 x+6$

$x^{2}+5 x-2 x-4-6=0$

$x^{2}+3 x-10=0$

Often, the value of x is easiest to solve by $a x^{2}+b x+c=0$ by factoring a square factor, setting each factor to zero, and then isolating each factor. Whereas sometimes the equation is too awkward or doesn't matter at all, or you just don't feel like factoring.

The Quadratic Formula: For $a x^{2}+b x+c=0$ , the values of x which are the solutions of the equation are given by:

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Where, a = 1, b = 3 and c = -10

$x=\frac{-3 \pm \sqrt{(-3)^{2}-4(1)(-10)}}{2(1)}$

$x=\frac{-3 \pm \sqrt{9+40}}{2}$

$x=\frac{-3 \pm \sqrt{49}}{2}=\frac{-3 \pm 7}{2}$

So, the solutions for ‘x’ are

$x=\frac{-3+7}{2}=\frac{4}{2}=2$

$x=\frac{-3-7}{2}=\frac{-10}{2}=-5$

The solutions for ‘x’ are 2 and -5

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3 years ago

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The answer would be B.

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3 years ago

last year fred earned $156 every week that he worked.he made a total of $4,680.how many weeks did he work

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3 years ago

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3 years ago