Answer:
<h2>The table is linear.</h2><h2 />
I'll try to explain it as best as I can.
The input's numbers do not match the output's numbers. Therefore, the graph is linear.
SA pyramid+SA rectangular prism= total SA
Total SA= Area of the base+ area of the four rectangles+area of four triangles
Total SA= length^2+length*width*4+1/2(slant height)(length)*4
length=12, width=8, slant height=10
Total SA= (12)^2+4(1/2*12*10) +4(12*8)=768cm^2
so C is correct.
If dilation is about the origin, and there is no translation, rotation, or reflection involved, the matrix of image coordinates is the matrix of original coordinates multiplied by the scalar dilation factor.
1.
![2.5\left[\begin{array}{ccc}-2&4&0\\-2&1&6\end{array}\right]=\left[\begin{array}{ccc}-5&10&0\\-5&2.5&15\end{array}\right]\\\\\text{Image coordinates are X'(-5,-5), Y'(10,2.5), Z'(0,15).}](https://tex.z-dn.net/?f=2.5%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2%264%260%5C%5C-2%261%266%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-5%2610%260%5C%5C-5%262.5%2615%5Cend%7Barray%7D%5Cright%5D%5C%5C%5C%5C%5Ctext%7BImage%20coordinates%20are%20X%27%28-5%2C-5%29%2C%20Y%27%2810%2C2.5%29%2C%20Z%27%280%2C15%29.%7D)
2.
![\dfrac{1}{4}\left[\begin{array}{ccc}0&5&4\\-1&-1&3\end{array}\right]=\left[\begin{array}{ccc}0&\frac{5}{4}&1\\-\frac{1}{4}&-\frac{1}{4}&\frac{3}{4}\end{array}\right]\\\\\text{Image coordinates are F'(0, -.25), G'(1.25, -.25), H'(1, .75).}](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7B4%7D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%265%264%5C%5C-1%26-1%263%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%26%5Cfrac%7B5%7D%7B4%7D%261%5C%5C-%5Cfrac%7B1%7D%7B4%7D%26-%5Cfrac%7B1%7D%7B4%7D%26%5Cfrac%7B3%7D%7B4%7D%5Cend%7Barray%7D%5Cright%5D%5C%5C%5C%5C%5Ctext%7BImage%20coordinates%20are%20F%27%280%2C%20-.25%29%2C%20G%27%281.25%2C%20-.25%29%2C%20H%27%281%2C%20.75%29.%7D)
<span>use the formula: Volume=1/3 x(times) the area of the base x(times) height</span>
Answer:
1.5
Step-by-step explanation:
3/2