Answer:
128 degrees, so C is again the answer.
Step-by-step explanation:
Since angles 3 and 11 are corresponding(from your previous question), angles 1 and 11 will add up to 180 degrees, since a line is that long. Therefore your answer is 180-(degrees of angle 1)= 180-52= 128
Answer:
The solution is (1,2)
Step-by-step explanation:
- 2x - y = - 4
x + 2y = 5
Multiply the second equation by 2 so we can eliminate x
2( x + 2y) = 5*2
2x +4y = 10
Add this to the first equation
- 2x - y = - 4
2x +4y = 10
----------------------
3y = 6
Divide each side by 3
3y/3 = 6/3
y = 2
- 2x - y = - 4
x + 2y = 5
Multiply the first equation by 2 to eliminate y
2(- 2x - y) = - 4*2
-4x -2y = -8
Add this to the second equation
-4x -2y = -8
x + 2y = 5
------------------
-3x = -3
Divide by -3
-3x/-3 = -3/-3
x = 1
The solution is (1,2)
Answer:
UW = 67
Step-by-step explanation:
UW = 6x - 35
VW = 4x - 20
UV = 19
So that means
4x - 20 + 19 = 6x - 35
4x - 1 = 6x - 35
-1 = 2x - 35
34 = 2x
x = 17
6(17) - 35
102 - 35 = 67
If my answer is incorrect, pls correct me!
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-Chetan K
Answer:
a) 1/2
b) 1/n
c) 1/4
Step-by-step explanation:
a) For each permutation, either 1 precedes 2 or 2 precedes 1. For each permutation in which 1 precedes 2, we can swap 1 and 2 to obtain a permutation in which 2 preceds 1. Thus, half of the total permutations will involve in 1 preceding 2, hence, the probability for a permutation having 1 before 2 is 1/2.
c) If 2 is at the start of the permutation, then it is impossible for 1 to be before 2. If that is not the case, then 1 has a probability of 1/n-1 to be exactly in the position before 2. We can divide in 2 cases using the theorem of total probability,
P( 1 immediately preceds 2) = P (1 immediately precedes 2 | 2 is at position 1) * P(2 is at position 1) + P(1 immediately precedes 2 | 2 is not at position 1) * P(2 is not at position 1) = 0 * 1/n + (1/n-1)*(n-1/n) = 1/n.
d) We can divide the total of permutations in 4 different groups with equal cardinality:
- Those in which n precedes 1 and n-1 precedes 2
- those in which n precedes 1 and 2 precedes n-1
- those in which 1 precedes n and n-1 precedes 2
- those in which 1 precedes n and 2 precedes n-1
All this groups have equal cardinality because we can obtain any element from one group from another by making a permutations between 1 and n and/or 2 and n-1.
This means that the total amount of favourable cases (elements of the first group) are a quarter of the total, hence, the probability of the event is 1/4.
³/14 cup of Debbie’s
Step-by-step explanation:
⁴/7 of ¾ is;
⁴/7 * ¾ = 12/28
= ³/7
Each friend gets ½ and ½
Therefore ½ of ³/7 is;
½ * ³/7 = ³/14
= ³/14 cup of Debbie’s
