Let's call the two numbers
and
.
Given these variables, we can say:
, based on the first sentence in the problem.
Also, remember that the reciprocal of a number is simply 1 divided by the number. Thus, we can say that:

To solve, we can simply substitute
in for
in the second equation and solve.


- Get terms on the left side to a common denominator for easier addition


- Cross multiplication (
)


- Subtract
from both sides of the equation

- Factor left side of the equation

Now, notice that we have found two solutions, but the problem is only asking for one. This <em>likely </em>means that one of our solutions is extraneous. Let's take a look. Remember that the smaller positive number is equal to 14 less than the larger number. However,
,
Since
is not positive in this case,
is not a solution.
Thus,
is our only solution. In this case,
,
which means that the smaller number is 14 and the larger number is 28.
Answer:
Alright well solve for z by simplifying by both sides of the equation, then isolating the variable
Exact form: z = 2/5
Decimal form: o.4 Hope this helps :)
Step-by-step explanation:
Where’s the graph or whatever???
Answer:
99.4194
Step-by-step explanation:
Hello
f(x) = 2sin(x)
f(<span>π/6) = 1
f'(x) 2cos(x)
f'(</span>π/6) = 2×co(π/6) = 2 × root(3)×0.5 =root(3)
The equation of this tangent line is : y= root(3)(x-π/6)+1
y = root(3)x+1 - π/6(root(x)) <span>in the form y=mx+b
m = root(3) and b = </span>1 - π/6(root(x))