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alukav5142 [94]
3 years ago
9

Does 2x-7=1/3(6x-12) + (-3) have one solution, infinitely many solutions, or no solutions? Please show how you got the answer an

d explain ty!!
Mathematics
2 answers:
salantis [7]3 years ago
7 0

Answer:

Infinetly many solutions. No matter what you plug in, it always comes out equal.

Step-by-step explanation:

babunello [35]3 years ago
3 0
It has many solutions.


2x - 7 = 1/3 x 3(2x - 4) - 3
2x - 7 = (2x - 4) - 3
2x - 7 = 2x - 4 - 3
-7 = - 4 - 3
-7 = -7
therefore it’s true meaning many solutions.
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What similarity statement can you write relating the three triangles in the diagram?
GarryVolchara [31]

Answer:

They are both right-angled triangles.

Step-by-step explanation:

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2 years ago
If you place a 24-foot ladder against the top of a 22-foot building, how many feet will the bottom of the ladder be from the bot
Naddika [18.5K]

Answer:

9.6

Step-by-step explanation:

Use the Pythagorean Theorem

a² + b² = c²

Plug in the knowns

a² + 22² = 24²

Subtract 22² from both sides

a² = 24² - 22²

a² = 576 - 484

a² = 92

Take the square root of both sides

a = 9.591663046625438

Rounded

a = 9.6 ft

8 0
3 years ago
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Find the maxmium area of a rectangular plot of land which can be enclosed by rope of length 60 metres​
mario62 [17]

Answer:

225 m²

Step-by-step explanation:

If W is the width of the rectangle, and L is the length, then:

60 = 2W + 2L

A = WL

Use the first equation to solve for one of the variables:

30 = W + L

L = 30 − W

Substitute into the second equation:

A = W (30 − W)

A = 30W − W²

This is a parabola, so we can find the vertex using the formula x = -b/(2a).

W = -30 / (2 × -1)

W = 15

Or, we can use calculus:

dA/dW = 30 − 2W

0 = 30 − 2W

W = 15

Solving for L:

L = 30 − W

L = 15

So the maximum area is:

A = WL

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3 0
3 years ago
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Step-by-step explanation:

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2 years ago
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Nana76 [90]

ANSWER

Domain: All real numbers

Range:

[2,  \infty )

EXPLANATION

The given function is

y = 3 {x}^{2}   - 6x  + 5

To find the domain and range of the given function, we complete the square.

y = 3 ({x}^{2}   - 2x  )+ 5

y = 3 ({x}^{2}   - 2x   + 1) + 3(  - 1)+ 5

y = 3 ({x - 1)}^{2}    - 3+ 5

y = 3 ({x - 1)}^{2}   + 2

The vertex is at (1,2).

The given function is a polynomial and all polynomial functions are defined everywhere.

The domain is all real numbers.

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The range is

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