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Marizza181 [45]
3 years ago
6

Why does air density decrease with increasing altitude within Earth's atmosphere?

Chemistry
1 answer:
kupik [55]3 years ago
5 0

Explanation:

As the altitude increases, the pressure and the density of the atmosphere decrease.

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How many grams of sodium chloride are required to make a 1.0 L solution with a concentration of 3.5 M? 205 grams 0.205 grams 3.5
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<span>A 1 molar solution is the molecular weight in grams in 1 litre of water, so a 3.5 molar solution would be 58.44g multiplied by 3.5, which is 204.54g in 1L.</span>
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When the number of protons and electrons is the same for an atom, the atom is
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A) Neutral.

Explanation:

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The reactants A and B react completely in a sealed container to form a product. What is the mass of the product of the reaction
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HELP HELP HELP HELP Please Help Will Mark Brainlyliest How does the amount and type of fuel impact the distance a spacecraft can
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Explanation:

Defining Emotional Appeal

An emotional appeal is used to sway the emotions of an audience to make them support the speaker’s argument.

LEARNING OBJECTIVES

Break down the components that make up an emotional appeal

KEY TAKEAWAYS

Key Points

Pathos represents an appeal to the emotions of an audience.

An emotional appeal uses the manipulation of the emotions rather than valid logic to win an argument.

Emotional appeal is a logical fallacy, whereby a debater attempts to win an argument by trying to get an emotional reaction from the opponent and audience.

In debating terms, emotional appeals are often effective as a rhetorical device, but are generally considered naive or dishonest as a logical argument, since they often appeal to the prejudices of listeners rather than offer a sober assessment of a situation.

Key Terms

logical fallacy: A fallacy; a clearly defined error in reasoning used to support or refute an argument, excluding simple unintended mistakes.

Emotional Appeal Defined

Pathos represents an appeal to the audience’s emotions. Pathos is a communication technique used most often in rhetoric (where it is considered one of the three modes of persuasion, alongside ethos and logos), and in literature, film, and other narrative art.

Emotional appeal can be accomplished in a multitude of ways:

By a metaphor or storytelling, common as a hook

By a general passion in the delivery

By an overall emotion

By the sympathies of the speech or writing as determined by the audience

The pathos of a speech or writing is only ultimately determined by the audience.

The Purpose of an Emotional Appeal

An emotional appeal is directed to sway an audience member’s emotions and uses the manipulation of the recipient’s emotions rather than valid logic to win an argument. An emotional appeal uses emotions as the basis of an argument’s position without factual evidence that logically supports the major ideas endorsed by the presenter. In an emotional appeal, persuasive language is used to develop the foundation of an appeal to emotion-based arguments instead of facts. Therefore, the validity of the premises that establish such an argument does not prove to be verifiable.

A US soldier holds his daughter and his son.

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Emotional appeal is a logical fallacy, whereby a debater attempts to win an argument by trying to get an emotional reaction from the opponent and audience. It is generally characterized by the use of loaded language and concepts (God, country, and apple pie being good concepts; drugs and crime being bad ones). In debating terms, emotional appeals are often effective as a rhetorical device, but are generally considered naive or dishonest as a logical argument, since they often appeal to the prejudices of listeners

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3 years ago
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I’ve been stuck on these 5 questions!? Can you guys help?!
Varvara68 [4.7K]

Answer:

1. 0.224 moles of oxygen

3. 143.36 L oxygen gas

5. 0.059 atm

10. 5.14 atm

11. 307 K

Explanation:

1. You have to use the ideal gas law: PV=nRT where P is pressure in atm, V is volume in liters, n is number of moles, R is the constant 0.08206 L atm mol^-1 K^-1, and T is the temperature in Kelvins where K=degrees celsius+273.15 . By rearranging the equation, you solve for n, which is n=(PV)/(RT)

P= 28.3 atm

V=0.193 L

R= 0.08206 L atm mol^-1 K^-1

T= 24.5+273.15= 297.65 K

Plugging the values in,

n=(28.3 atm x 0.193 L)/(0.08206 L atm mol^-1 K^-1 x 297.65 K)

n= 0.224 moles of oxygen

3. At STP, there are 22.4 L of gas for every mole of gas present. So 6.4 moles of oxygen would mean that there are:

6.4 mol x 22.4 L= 143.36 L oxygen gas

5. You have to use the ideal gas law: PV=nRT where P is pressure in atm, V is volume in liters, n is number of moles, R is the constant 0.08206 L atm mol^-1 K^-1, and T is the temperature in Kelvins where K=degrees celsius+273.15 . By rearranging the equation, you solve for P, which is       P=(nRT)/V

n= 0.72 g converting to moles, divide by molar mass of oxygen gas:        0.72 g/32g= 0.0225 moles

V=9.3 L

R= 0.08206 L atm mol^-1 K^-1

T= 23.0+273.15= 296.15 K

Plugging the values in,

P=(0.0225 moles x 0.08206 L atm mol^-1 K^-1 x 296.15 K)/ 9.3 L

P= 0.059 atm

10. Ideal gas law again using the same equation as 5 above: You have to use the ideal gas law: PV=nRT where P is pressure in atm, V is volume in liters, n is number of moles, R is the constant 0.08206 L atm mol^-1 K^-1, and T is the temperature in Kelvins where K=degrees celsius+273.15 . By rearranging the equation, you solve for P, which is P=(nRT)/V

n= 0.108 mol

R=0.08206 L atm mol^-1 K^-1

T=20.0+273.15= 293.15 K

V= 0.505 L

Plugging the values in,

P=(0.108 mol x 0.08206 L atm mol^-1 K^-1 x 293.15 K)/0.505 L

P= 5.14 atm

11. You have to use the ideal gas law: PV=nRT where P is pressure in atm, V is volume in liters, n is number of moles, R is the constant 0.08206 L atm mol^-1 K^-1, and T is the temperature in Kelvins where K=degrees celsius+273.15 . By rearranging the equation, you solve for Y, which is T=(PV)/(nR)

P= 0.988 atm

V= 1.20 L

n= 0.0470 mol

R=0.08206 L atm mol^-1 K^-1

Plugging the numbers in,

T=(0.988 atm x 1.20 L)/(0.0470 mol x 0.08206 L atm mol^-1 K^-1)

T= 307 K

4 0
3 years ago
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