The equilibrium constant expression for this reaction that takes place in water and involve ions can be written as K= [H_3 O^+ ][OH^- ]/([H_2 O] ^2 ). But the concentration of undissociated water, H_2 O is much larger than the concentration of the ions that is essentially remains constant. Therefore, we can include it in the equilibrium constant. The resulting new equilibrium constant can be written: K_W= [H_3 O^+ ][OH^- ].
The pressure of the gas is 3.52 atm
<u><em>calculation</em></u>
This is calculated using the Boyle's law formula
that is P1V1= P2V2 where;
P1 = 1.65 atm
V1 =22.8 L
P2 =? atm
V2 = 10.7 L
make P2 the subject of the formula by dividing both side by V2
P2 = P1V1 / V2
P2 = (1.65 atm x 22.8 l) / 10.7 L = 3.52 atm
In the past, restaurants had four hours, straight through, to cool food to 41°F or lower. Now the FDA recommends cooling food in two stages -- from 135°F to 70°F in two hours then from 70°F to 41°F or lower in an additional four hours for a total cooling time of six hours
Explanation:
the two-stage cooling method<span> is a </span><span>Food Code </span>counselled<span> procedure for cooling food in restaurants and foodservice </span>institutions<span>. </span>within the<span> two-stage cooling </span>methodology<span>, food is</span><span> cooled from 140° F (60° C) to 70° F (21° C) </span>among 2<span> hours and to 41° F (5° C) or lower </span>among<span> four hours. Use of this cooling </span>methodology<span> ensures that food is cooled quickly and safely and has no harmful effects.</span>
Answer:
The common oxide of nitrogen that has a positive ΔS°f is nitric oxide (NO)
Explanation:
Without reference to thermodynamic data, we have;
1) N₂ (g) + O₂ (g) ⇄ 2 NO (g)
1 unit of N₂ + 1 unit of O₂ (total of 2 units) gives 2 units of NO, (Increase of +0 disorder)
∴ΔS°f = +ve
2) 2NO + O₂ → 2NO₂
2 unit of NO + 1 unit of O₂ (total of 3 units) gives 2 units of NO₂, (Decrease of disorder)
∴ΔS°f = -ve
3) N₂ + 1/2 O₂ → N₂O
1 unit of N₂ + 1/2 unit of O₂ (total of 1+1/2 units) gives 2 units of NO₂, (Decrease of disorder)
∴ΔS°f = -ve
4) 4 NO₂ + O₂ → 2N₂O₅
4 unit of NO₂ + 1 unit of O₂ (total of 5 units) gives 2 units of N₂O₅, (Decrease of disorder)
∴ΔS°f = -ve
5) NO + NO₂ ⇄ N₂O₃
1 unit of NO + 1 unit of NO₂ (total of 2 units) gives 1 unit of N₂O₃, (Decrease of disorder)
∴ΔS°f = -ve
Therefore, the common oxide of nitrogen that has a positive ΔS°f without reference to thermodynamic data is nitric oxide NO.
An electrolyte is a substance that releases ions when it is dissolved in water. Electrolytes are divided into salts, ions and bases. In this case, the electrolyte is H₃PO₄ as it releases H+ ions and PO₄⁻³ ions when it is dissolved in water.
