Answer:
When the sample size is increased from n = 9 to n = 45, the standard deviation of the sample mean decreases from 1.167 to 0.522.
Step-by-step explanation:
The Central Limit Theorem estabilishes that, for a random variable X, with mean and standard deviation , the sample means with size n can be approximated to a normal distribution with mean and standard deviation
In this problem, we have that:
n = 9
n = 45
When the sample size is increased from n = 9 to n = 45, the standard deviation of the sample mean decreases from 1.167 to 0.522.
I see you're probably trying to use a math editor to present this problem. Unfortunately, I'm unsure how to decipher your "-\frac {a }{8.06)." What fraction are you speaking of?
Given "<span>#-\frac { a } { 8.06} + 7.02= 18.4#," all I can say with certainty is that you could legitimately subtract 7.02 from both sides:
</span><span>#-\frac { a } { 8.06} + 7.02= 18.4#
- 7.02 = -7.02
After I've heard back from you, I'll try to help you solve the entire problem.
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9(4r-6) it is in factor form.
Πr^2 - the base of a cone is a circle, so use the equation for area of a circle