The description below proves that the perpendicular drawn from the vertex angle to the base bisect the vertex angle and base.
<h3>How to prove an Isosceles Triangle?</h3>
Let ABC be an isosceles triangle such that AB = AC.
Let AD be the bisector of ∠A.
We want to prove that BD=DC
In △ABD & △ACD
AB = AC(Thus, △ABC is an isosceles triangle)
∠BAD =∠CAD(Because AD is the bisector of ∠A)
AD = AD(Common sides)
By SAS Congruency, we have;
△ABD ≅ △ACD
By corresponding parts of congruent triangles, we can say that; BD=DC
Thus, this proves that the perpendicular drawn from the vertex angle to the base bisect the vertex angle and base.
Read more about Isosceles Triangle at; brainly.com/question/1475130
#SPJ1
Answer:
No
Step-by-step explanation:
The two shorter lengths won't make a triangle of any kind.
They will simply form a straight line parallel to the base.
(2x-3)(x+4) —> x= 3/2 x= -4
Answer:
B 34
Step-by-step explanation:
The arc is 1/2 the same measure of the angle.
<y = 1/2 arc xz
<y = 1/2 (68)
<y = 34
