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ss7ja [257]
3 years ago
8

3x%2B5%7D%20%5Catop%20%7By%3D-4x%2B7%7D%7D%20%5Cright.%5C%5C%5C%5C%5Ctext%7BThank%20you.%7D" id="TexFormula1" title="\text{Solve the system of equations:}\\\\\left \{ {{y=3x+5} \atop {y=-4x+7}} \right.\\\\\text{Thank you.}" alt="\text{Solve the system of equations:}\\\\\left \{ {{y=3x+5} \atop {y=-4x+7}} \right.\\\\\text{Thank you.}" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Anika [276]3 years ago
4 0

Hi there!  

»»————- ★ ————-««

I believe your answer is:  

(0.286, 5.587)

»»————- ★ ————-««  

Here’s why:  

⸻⸻⸻⸻

  • I have graphed the two equations in a program. When graphed, the lines intersect at point (0.286, 5.587).
  • See the graph attached.

⸻⸻⸻⸻

»»————- ★ ————-««  

Hope this helps you. I apologize if it’s incorrect.  

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Aljan and Bella are both driving from Cleveland to Chicago. Aljan leaves at
Natalija [7]

Answer:

Bella will pass Ajjan after 4h and they will have travelled 260 miles.

Step-by-step explanation:

In order to calculate the number of hours, "x", that it'll take for Bella to pass Aljan, we need to find the value of "x" that makes both equations equal. Therefore,

60*x + 20 = 65*x\\65*x - 60*x = 20\\5*x = 20\\x = \frac{20}{5} = 4

In order to calculate the distance they traveled, we must use this value for "x" in any of the equations, as done below:

y = 65*4\\y = 260

Bella will pass Ajjan after 4h and they will have travelled 260 miles.

4 0
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6 0
3 years ago
If f(x) = 4 – x2 and g(x) = 6x, which expression is equivalent to (g – f)(3)?
Kryger [21]

For this case we have the following functions:

f (x) = 4 - x ^ 2\\g (x) = 6x

The first thing we must do for this case is to subtract both functions.

We have then:

(g - f) (x) = g (x) - f (x)

Substituting we have:

(g - f) (x) = (6x) - (4 - x ^ 2)

Rewriting we have:

(g - f) (x) = x ^ 2 + 6x - 4

Evaluating the obtained function for x = 3 we have:

(g - f) (3) = (3) ^ 2 + 6 (3) - 4\\(g - f) (3) = 23

Answer:

The value of the function evaluated at x = 3 is:

(g - f) (3) = 23

7 0
3 years ago
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