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Mrrafil [7]
3 years ago
8

What's the answer guys?

Mathematics
2 answers:
likoan [24]3 years ago
8 0

Answer: 14.4p - 2.2q + 4.3r

Step-by-step explanation:

(8.8p + 5.6p) + (6.2q - 8.4q) + (-1.8r + 6.1r)

= 14.4p - 2.2q + 4.3r

please give me a brainliest answer

MAXImum [283]3 years ago
4 0

Answer:

Step-by-step explanation:

Ask your parents

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A tree outside Dave’s house is 12 feet tall
Oxana [17]

Answer:

wheres the reszt of the question?

Step-by-step explanation:

4 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Cbegin%7Bequation%7D%5Ctext%20%7B%20Question%3A%20Find%20the%20value%20of%20%7D%20%5Cfrac%7B
ankoles [38]

\bold{Heya!}

Your answer to this is:

\sf{= \frac{1}{2} \: + \frac{2}{1 \: + \: x^2} \: + \: \frac{1}{1 \: + \: x^4} \: + \: \frac{2^1^0^0}{1 \: + \: x^2^0^0}

<h2>→ <u>EXPLANATION :-</u></h2>

<u />

<u />\sf{= \frac{1}{2} \: + \frac{2}{1 \: + \: x^2} \: + \: \frac{1}{1 \: + \: x^4} \: + \: \frac{2^1^0^0}{1 \: + \: x^2^0^0} \: (1)

\sf{Apply \: rule:} \: (a) = a

\sf{(1) = 1

\sf{= \frac{1}{2} \: + \frac{2}{1 \: + \: x^2} \: + \: \frac{1}{1 \: + \: x^4} \: + \: \frac{2^1^0^0}{1 \: + \: x^2^0^0} \: ^. \: 1

\sf{\frac{1}{1 \: + \:1} = \frac{1}{2}

\sf{\frac{2^1^0^0}{1 \: + \: x^2^0^0} ^.^ \: 1 \: = \: \frac{2^1^0^0}{1 \: + \: x^2^0^0}

\sf{= \frac{1}{2} \: + \frac{2}{1 \: + \: x^2} \: + \: \frac{1}{1 \: + \: x^4} \: + \: \frac{2^1^0^0}{1 \: + \: x^2^0^0}

Hopefully This Helps ! ~

#LearnWithBrainly

\underline{Answer :}

<em>Jaceysan ~</em>

7 0
1 year ago
Match each whole number with a rational, exponential expression.
Katyanochek1 [597]

1.\\9=3^2\\2.\\196=14^2\\3.\\256=16^2=4^4=2^8\\4.\\225=15^2\\5.\\16=4^2=2^4\\6.\\25=5^2

4 0
3 years ago
Find the area of the region bounded by the y-axis, the line y=6, and the line y = 1/2.
Ghella [55]

Solution:

As region bounded by y-axis, the line y=6, and the line y=1/2 is a line segment of definite length on y-axis.

We consider a line , one dimensional  if it's thickness is negligible.

So, Line is  two dimensional if it's thickness is not negligible becomes a quadrilateral.

So, Area (region bounded by y-axis, the line y=6, and the line y=1/2 is a line segment of definite length on y-axis)= Area of line segment between [,y=6 and  y=1/2.]= 6-1/2=11/2 units if we consider thickness of line as negligible.

4 0
3 years ago
Hew hats the LCM of 6 and 4
Simora [160]
That would be 2 because you can divide both by 2 and get a whole number hope this helps
8 0
3 years ago
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