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2 years ago

What is –4b + 8c + 12 – 8b – 2c + 6 simplifyed ?

Mathematics

1 answer:

Ede4ka [16]2 years ago

6 0

Answer:

Answer!!!!!

-12b + 6c + 18

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HELP MEE BRAINLIEST PLZZZZ!!!!

wel

The 3rd one

This is because in the graph it’s looking for numbers 70-79 but only with 2 numbers and the 3rd is the only one that fits in the description.

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3 years ago

The price of a technology stock has dropped to $9.79 yesterday. Today. the price fell to $9.68. Find the percentage decrease.

Citrus2011 [14]

The answer is 1.12% decrease
Explanation in image

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3 years ago

An ANOVA procedure is used for data obtained from four populations. Four samples, each comprised of 30 observations, were taken

tatiyna

Answer:

D. 3 and 116

Step-by-step explanation:

d.f.N = k - 1 (numerator degrees of freedom) = 4 - 1 = 3

N = 4 × 30 = 120

d.f.D = N - k (denominator degrees of freedom) = 120 - 4 =116

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3 years ago

PLZZZZZZ HELPPPPP

Makovka662 [10]

Answer:

(D)

Step-by-step explanation:

The graph shows the arm span lengths of the students, clearly we can see that the most of the students have arm span length in the initial points of the length.

Median = Middle frequency of the data. Here, median will be the length in the middle.

Mode = Most frequently occurring number in the data. Here the mode will be the length which most of the students has.

Clearly, most of the student has the length in the initial inches while the median will be in the middle.

Hence, mode will be less than the median.

8 0

3 years ago

Read 2 more answers

Reyesburg Corporation is contemplating using a new, more expensive glue in the construction of its laminated veneer lumber. Of i

Leokris [45]

Answer:

The mean carrying load of the beams tested is 908.7 pounds per square foot

Step-by-step explanation:

1. Data class 1: 860-879

Midpoint 1: M1=(860+879)/2=1,739/2→M1=869.5

Number of values in data class 1: n1=2

2. Data class 2: 880-899

Midpoint 2: M2=(880+899)/2=1,779/2→M2=889.5

Number of values in data class 2: n2=5

3. Data class 3: 900-919

Midpoint 3: M3=(900+919)/2=1,819/2→M3=909.5

Number of values in data class 3: n3=10

4. Data class 4: 920-939

Midpoint 4: M4=(920+939)/2=1,859/2→M4=929.5

Number of values in data class 4: n4=6

5. Data class 5: 940-959

Midpoint 5: M5=(940+959)/2=1,899/2→M5=949.5

Number of values in data class 5: n5=1

Mean=Sum(Mi*ni)/Sum(ni)

Mean=(M1*n1+M2*n2+M3*n3+M4*n4+M5*n5)/(n1+n2+n3+n4+n5)

Mean=(869.5*2+889.5*5+909.5*10+929.5*6+949.5*1)/(2+5+10+6+1)

Mean=(1,739+4,447.5+9,095+5,577+949.5)/(24)

Mean=(21,808)/(24)

Mean=908.6666666

Rounding to one decimal place:

Mean=908.7

3 0

3 years ago