Answer: none
Step-by-step explanation:
(A)
(16÷32/10) ×2 + 0.2×(90)
Using bodmas principle ; solve bracket
(16×10/32)×2 + (2/10×90)
10+18 =28
(B)
{(16÷32/10) × (2+2/10)} ×90
Open brackets
{(16×10/32) × (22/10)} ×90
(5×11/5) ×90
11×90 = 990
(C)
16÷{(32/10×2) + (2/10×8)} +82
Open brackets, solve division first, dolled by addition
16÷(32/5 + 8/5) +82
16÷(40/5) +82
16÷8 +82
2+82= 84
(D)
[16÷(32/10 ×2) + 0.2× (90)]
16÷ (32/5) + 2/10 ×90
Solve division
16×5/32 + 18
5/2 + 18
L.c.m of denominator (2&1) =2
(5+36) / 2 = 41/2
=20.5
The probability of picking a blue jelly bean is 10/12=0.833, since there are 10 blue and 12 jelly beans in total.
Each time the probability of picking blue is the same, since put back in the box whatever jelly bean we pick
P(blue, blue, blue) = P(blue) × P(blue) × P(blue) = 0.833×0.833×0.833=0.579
Answer: 0.579
Answer:
75 percent
Step-by-step explanation:
see the thing is
C. The number of times a dessert was offered at a special price.
A is the answer I got hope this helps !!
