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RSB [31]
3 years ago
12

A consumer group claims that the average annual consumption of high fructose corn syrup by a person in the U.S. is 48.8 pounds.

You believe it is higher. You take a simple random sample of 35 people in the U.S. and find an average of 53.8 pounds with a standard deviation of 4.4 pounds. Test at 1% significance. Round to the fourth
Mathematics
1 answer:
LenaWriter [7]3 years ago
6 0

Answer:

6.7159

Step-by-step explanation:

\mu=48.8\\n=35\\\bar{x}=53.8\\\sigma=4.4\\\alpha=1\%=0.01

Null and alternative hypothesis :

H_0:\mu=48.8\\H_a:\mu>48.8

Test statistic,

t=\frac{\bar{x}-\mu}{\frac{\sigma}{\sqrt{n}}}

\Rightarrow t=\frac{53.8-48.8}{\frac{4.4}{\sqrt{35}}}

\Rightarrow t=\frac{5\times 5.91}{4.4}

\Rightarrow t=6.715

Test statistic t=6.715

P-value =P(t>6.715)

P- value =0.0001  by the p- table

Significance level 0.01

         p-value

  We reject H_0

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