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3 years ago

What if 1/3 years = -------- month

Mathematics

2 answers:

adell [148]3 years ago

7 0

Answer: 4 months

Step-by-step explanation:I believe it would be four months because 12 months in a year divided by 1/3 would be 4 months. Hope this helps!

Leviafan [203]3 years ago

5 0

Answer: 1/3 of a year equals 4 months

Step-by-step explanation: This is because there are 12 months in a year and 1/3 years is 12/3, which is 4

Hope you are having a nice day and please tell me If got anything wrong

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Please help! What is the function for the graph

Evgen [1.6K]

When x = 0 the value of the function is 2 so its either A or B.

When x = 1, y = 8 so substituting these values in A we get:-

8 = 2 * 8^1 = 16 so

its Not A. Try B:-

8 = 2 *4^1 = 8 which fits

Answer is choice B

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3 years ago

Find the distance between the two points in simplest radical form.

Jlenok [28]

Answer:

$d=\sqrt{58}\approx7.6$

Step-by-step explanation:

To find the distance between any two points, we can use the distance formula:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2$

Our first point, A, is at (1, 1) and our second point, B, is at (-2, 8).

Let's let A(1, 1) be (x₁, y₁) and B(-2, 8) be (x₂, y₂). Substitute this into the distance formula:

$d=\sqrt{(-2-1)^2+(8-1)^2$

Subtract:

$d=\sqrt{(-3)^2+(7)^2$

Square:

$d=\sqrt{9+49}$

Add:

$d=\sqrt{58}$

This cannot be simplified.

So, the distance between the two points is √58 or about 7.6 units.

And we're done!

So... where's my cookie :)?

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3 years ago

Find the LCD to each the fractions and then add them together 1/4 + 2/5 + 1/3

jekas [21]

The LCD of these fractions is 60!

The sum of these fractions is $\frac{59}{60}$ !

⭐ Please consider brainliest! ⭐

✉️ If any further questions, inbox me! ✉️

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2 years ago

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Vinil7 [7]

Answer:

x=0

Step-by-step explanation:

substitute y=0

0= -x^2

then swap the sides

-x^2=0 ,

change the signs

x^2=0

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2 years ago

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svetoff [14.1K]

Answer:hope help

Step-by-step explanation:

Find the range by listing all the y values from the ordered pairs. Repeated values within the domain or range don't have to be listed more than once. In order for a relation to be a function, each x must correspond with only one y value.

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2 years ago

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