I did this excat problem in school but my teacher just gave us the answer which is X<2
height = 15 cm
the volume (V) of a cylindrical can is
V = πr²h ( r is the radius and h the height )
here d = 8 cm ⇒ r = 4 cm
π × 4² × h = 753.6
16πh = 753.6 ( divide both sides by 16π )
h = 753.6 / 16π = 14.99 ≈ 15 cm
Answer:
A) A(t) = 4500*π - 1600*t
B) A(4) = 7730 in³
C) t = 8,8 sec
Step-by-step explanation:
The volume of the sphere is:
d max = 30 r max = 15 in
V(s) = (4/3)*π*r³ V(s) = (4/3)*π* (15)³
V(s) = 4500*π
A) Amount of air needed to fill the ball A(t)
A(t) = Total max. volume of the sphere - rate of flux of air * time
A(t) = 4500*π - 1600*t in³
B) After 4 minutes
A(4) = 4500*π - 6400
A(4) = 14130 - 6400
A(4) = 7730 in³
C) A(t) = 4500*π - 1600*t
when A(t) = 0 the ball got its maximum volume then:
4500*π - 1600*t = 0
t = 14130/1600
t = 8,8 sec
Answer:
This one ↓↓↓↓↓↓
Step-by-step explanation:
The picture attached is the reflection over the line y = 0
-Chetan K
<span>2(7/9)-(1/4) = 47/36 = 1 11/36</span>
