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Luden [163]
3 years ago
11

Question one pls algebra 2 logarithms

Mathematics
1 answer:
nirvana33 [79]3 years ago
4 0

Condense the logarithm on the right side:

3\log_b(p)-\left(2\log_b(t)+\dfrac12\log_b(r)\right)

n\log_b(m)=\log_b(m^n) \implies \log_b(p^3)-\left(\log_b(t^2)+\log_b\left(r^{\frac12}\right)\right)

\log_b(m)+\log(n)=\log_b(mn) \implies \log_b(p^3)-\log_b\left(t^2r^{\frac12}\right)

\log_b(m)-\log(n)=\log_b\left(\dfrac mn\right) \implies \log_b\left(\dfrac{p^3}{t^2r^{\frac12}}\right)

So,

x=\dfrac{p^3}{t^2r^{\frac12}}

and r^{\frac12}=\sqrt{r}, which makes (4) the correct choice.

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4 years ago
Four times the sum of a number and 3 is the same as the sum of two times the number and 8. Find the number.
tino4ka555 [31]

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Step-by-step explanation:

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x = -2                <-------divide both sides by 2 which leaves a negative answer

Third, we want to check the answer by substituting the value of -2 for x in the original equation.

4 (x + 3) = 2x + 8

4 (-2 +3) = 2(-2) + 8

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  4        =      4

4 (x + 3) = 2x + 8   <----"four times the sum of a number and three is equal to eight more than twice the number."

Second, we want to solve the equation:

4 (x + 3) = 2x + 8

4x + 12 = 2x + 8

2x + 12 = 8       <-------subtract 2x from both sides of the equation.

2x = -4              <-------subtract -12 from both sides

x = -2                <-------divide both sides by 2 which leaves a negative answer

Third, we want to check the answer by substituting the value of -2 for x in the original equation.

4 (x + 3) = 2x + 8

4 (-2 +3) = 2(-2) + 8

-8 + 12 = -4 + 8

  4        =      4

8 0
3 years ago
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As given,  

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x + 4 =  55 * 58 / 63.8 =  50

x = 46 
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3 years ago
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