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uysha [10]
3 years ago
10

What is the surface area of the triangular prism?​

Mathematics
2 answers:
yan [13]3 years ago
6 0

Answer:

(B) 2,376

Step-by-step explanation:

I was the first person to actually answer since the other person used you for points but it is B

Inessa05 [86]3 years ago
4 0

Answer:

9 x 24 x 1/2(basically dividing by 2) = 108 , 108  x 2(two triangles) = 216

40 x 15 = 600, 600 x 2(two slanted rectangles) = 1200

40 x 24 = 960 (area of base)

Add given areas:

216 + 1,200 + 960 = 2,376 square feet, B.

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If f(x) = 3x -11 , find -4f (-3)
gladu [14]

Answer:

80

Step-by-step explanation:

-4f(x)=-12x+44

-4f(-3)=36+44=80

6 0
3 years ago
Show detail for answering a larger number is five more than twice a smaller number Their sum is 80 find the numbers
tatyana61 [14]
20 times 4= 80 and ...

4 0
3 years ago
Complete the equation of the line whose slope is 5 and y intercept is (0,4)
irina1246 [14]

y = 5x + 4 is the equation of the line whose slope is 5 and y intercept is (0,4)

<em><u>Solution:</u></em>

Given that, we have to write the equation of the line whose slope is 5 and y intercept is (0,4)

<em><u>The equation of line in slope intercept form is given as:</u></em>

y = mx + c ---- eqn 1

Where, "m" is the slope of line and "c" is the y - intercept

Given that, slope = m = 5

y intercept is (0, 4)

So, c = 4

<em><u>Substitute c = 4 and m = 5 in eqn 1</u></em>

y = 5x + 4

Thus the equation of line is found

7 0
4 years ago
Rosa has blue cubes with a edge length of 55 mm and red cubes with a edge length of 45 mm. She wants to stack up the cubes in tw
VMariaS [17]

Answer:

?

Step-by-step explanation:

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3 0
3 years ago
Find the outward flux of the vector field f=(x3,y3,z2) across the surface of the region that is enclosed by the circular cylinde
ahrayia [7]
Use the divergence theorem.

\mathbf f(x,y,z)=(x^3,y^3,z^3)\implies \nabla\cdot\mathbf f=3(x^2+y^2+z^2)

Calling the closed region \mathcal R and its boundary the surface \partial\mathcal R, we have by the divergence theorem,

\displaystyle\underbrace{\iint_{\partial\mathcal R}\mathbf f\cdot\mathrm d\mathbf S}_{\text{flux}}=\iiint_{\mathcal R}\nabla\cdot\mathbf f\,\mathrm dV

We set up the volume integral in cylindrical coordinates, using

\begin{cases}x=u\cos v\\y=u\sin v\\z=w\end{cases}\implies\mathrm dV=u\,\mathrm du\,\mathrm dv\,\mathrm dw

\displaystyle\iiint_{\mathcal R}\nabla\cdot\mathbf f\,\mathrm dV=3\int_{w=0}^{w=6}\int_{v=0}^{v=2\pi}\int_{u=0}^{u=8}(u^2\cos^2v+u^2\sin^2v+w^2)u\,\mathrm du\,\mathrm dv\,\mathrm dw
=6\pi\displaystyle\int_{w=0}^{w=6}\int_{u=0}^{u=8}(u^3+uw^2)\,\mathrm du\,\mathrm dw=50,688\pi
7 0
3 years ago
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