Answer:
The answer is c because of how the equation is set and made
Answer:
I am not sure this is graphable
Step-by-step explanation:
There needs to be an = sign
Answer:
No order Pair fall on the graph
Step-by-step explanation:
The given Function is
...............(i)
Now to see whether these ordered pairs Lay on it we will put each ordered pair in the equation (i)
Lets take first ordered pair (1,1)
here x = 1
putting it in (i) gives
this is not equal to 1 so the order pair (1,1) does not fall on function
Lets take second ordered pair (-1,-4)
here x = -1
putting it in (i) gives
this is not equal to -4 so the order pair (-1,4) does not fall on function
Lets take third ordered pair (-2,-1/8)
here x = -2
putting it in (i) gives
this is not equal to -1/8 so the order pair (-2,1/8) does not fall on function
Lets take fourth ordered pair (0,-1/2)
here x = 0
putting it in (i) gives
this is not equal to -1/2 so the order pair (0,-1/2) does not fall on function
Answer:
The solution of the given equations are (3,2).
Step-by-step explanation:
Given equations are :
3d−e=7 ...(1)
d+e=5 ...(2)
Add equations (1) and (2) we get :
3d-e+d+e=7+5
4d = 12
d = 3
Put the value of d in equation (2).
3+e=5
e = 2
So, the value of d = 3 and e = 2. Solution of the given equations are (3,2).
Complete question :
According to the National Association of Realtors, it took an average of three weeks to sell a home in 2017. Suppose data for the sale of 39 randomly selected homes sold in Greene County, Ohio, in 2017 showed a sample mean of 3.6 weeks with a sample standard deviation of 2 weeks. Conduct a hypothesis test to determine whether the number of weeks until a house sold in Greene County differed from the national average in 2017. Useα = 0.05for the level of significance, and state your conclusion
Answer:
H0 : μ = 3
H1 : μ ≠ 3
Test statistic = 1.897
Pvalue = 0.0653
fail to reject the Null ; Hence, we conclude that their is no significant to accept the claim that number I weeks taken to sell a house differs.
Step-by-step explanation:
Given :
Sample size, n = 40
Sample mean, x = 3.6
Population mean, μ = 3
Standard deviation, s = 2
The hypothesis :
H0 : μ = 3
H1 : μ ≠ 3
The test statistic :
(xbar - μ) ÷ (s/√n)
(3.6 - 3) / (2/√40)
0.6 / 0.3162277
Test statistic = 1.897
Using T test, we can obtain the Pvalue from the Test statistic value obtained :
df = n - 1; 40 - 1 = 39
Pvalue(1.897, 39) = 0.0653
Decison region :
If Pvalue ≤ α ; Reject the null, if otherwise fail to reject the Null.
α = 0.05
Pvalue > α ; We fail to reject the Null ; Hence, we conclude that their is no significant to accept the claim that number I weeks taken to sell a house differs.
