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2 years ago

URGENT HELP PLEASEE SBDHHDS

Mathematics

1 answer:

11111nata11111 [884]2 years ago

5 0

Answer:

17800

Step-by-step explanation:

a= (t-g)/-0.0035

(-32.3-30)/-0.0035 = 17800

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Tickets to a school play cost $3 for each student and $8 for each parent. What would be the best choice for variable(s) when wri

algol13

Best choice for variables.....I would let students be " s " and parents be " p "

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2 years ago

If a dart board was thrown randomly at the dartboard shown below, what is the probability that it will land in the bull’s-eye? T

vampirchik [111]

Answer:

Correct option: C -> 2%

Step-by-step explanation:

To find this probability we just need to divide the area of the bull's-eye circle by the total area of the outer circle.

The area of a circle is given by the equation:

$area = \pi * radius^2$

The outer radius is 14 cm, so:

$outer\ area = \pi * 14^2 = 196\pi\ cm^2$

The inner radius is 2 cm, so:

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So the probability is:

$inner\ area / outer\ area = 4\pi / 196\pi = 0.02 = 2\%$

Correct option: C

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2 years ago

State the domain plssssa

Elza [17]

Answer:

I think it's {3, 6, 12, 18}

Step-by-step explanation:

Domain: all x-values that are to be used (independent values).

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2 years ago

Find the x-coordinates of any relative extrema and inflection point(s) for the function f(x) = 6x(1/3) + 3x(4/3). You must justi

stealth61 [152]

Applying our power rule gets us our first derivative,

$\rm f'(x)=6\frac13x^{-2/3}+3\cdot\frac43x^{1/3}$

simplifying a little bit,

$\rm f'(x)=2x^{-2/3}+4x^{1/3}$

looking for critical points,

$\rm 0=2x^{-2/3}+4x^{1/3}$

We can apply more factoring.
I hope this next step isn't too confusing.
We want to factor out the smallest power of x from both terms,
and also the 2 from each.

$0=2x^{-2/3}\left(1+2x\right)$

When you divide x^(-2/3) out of x^(1/3),
it leaves you with x^(3/3) or simply x.

Then apply your Zero-Factor Property,

$\rm 0=2x^{-2/3}\qquad\qquad\qquad 0=(1+2x)$

and solve for x in each case to find your critical points.

Apply your First Derivative Test to further classify these points. You should end up finding that x=-1/2 is an relative extreme value, while x=0 is not.

Let's come back to this,

$\rm f'(x)=2x^{-2/3}+4x^{1/3}$

and take our second derivative.

$\rm f''(x)=-\frac43x^{-5/3}+\frac43x^{-2/3}$

Looking for inflection points,

$\rm 0=-\frac43x^{-5/3}+\frac43x^{-2/3}$

Again, pulling out the smaller power of x, and fractional part,

$\rm 0=-\frac43x^{-5/3}\left(1-x\right)$

And again, apply your Zero-Factor Property, setting each factor to zero and solving for x in each case. You should find that x=0 and x=1 are possible inflection points.

Applying your Second Derivative Test should verify that both points are in fact inflection points, locations where the function changes concavity.

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3 years ago

What is the area?? Please help

Olegator [25]

Answer:

Step-by-step explanation:

We have the triangle and the rectangle.

The formula of an area of a triangle:

$A_{\triangle}=\dfrac{1}{2}bh$