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Minchanka [31]
3 years ago
9

How do i draw this for this problem?

Mathematics
2 answers:
yKpoI14uk [10]3 years ago
6 0
Try to use the ruler
tekilochka [14]3 years ago
4 0

Well, an angle bisector is a ray that "bisects" or cuts an angle in half, so, 64/2 = 32. Based off of my understanding of this picture, I would say that you have to drag the dot from point D to about halfway between each side, or, if it gives you the measurement while your moving it, move it to 32° on each side. If that doesn't work, I would try watching the help video :)

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Can 8/45 be simplified as a fraction
max2010maxim [7]

Answer:

Step-by-step explanation:

isn't it already a fraction or is it a division

if it's a division then yes

the answer is 5 and 2/8

8 0
3 years ago
Which value of the 9 ten times in the number 920
umka21 [38]

Answer:

9000. the value of 9 in 920 is 900. and ten times anything is basically just adding a 0. so ten times 900 is 9000.

Step-by-step explanation:

Please mark brainliest and have a great day!

3 0
3 years ago
How do you find the slop and y intercept of a graph
NemiM [27]
Y=mx+b is the formula you use to find the answer
7 0
3 years ago
In a geometric sequence, A1 = 0.3 and r=3.Find A12, to the nearest integer
soldi70 [24.7K]

Step-by-step explanation:

We have,

First terms of geometric sequence, a = 0.3

Common ratio, r = 3

It is required to find the 12th term of a GP. The formula of the nth term is given by :

T_n=ar^{n-1}

Here, n =12

So,

T_{12}=0.3\times 3^{12-1}\\\\T_{12}=0.3\times 3^{11}\\\\T_{12}=53144.1

or

T_{12}=53144

So, the 12th term of the GP is 53144.

8 0
3 years ago
What are all the exact solutions of -3tan^2(x)+1=0? Give your answer in radians.
goldenfox [79]
   
\displaystyle\\
 -3\tan^2x + 1 = 0\\\\
 -3\tan^2x = -1\\\\
\tan^2x =  \frac{-1}{-3} \\\\
\tan^2x =  \frac{1}{3} ~~~~~ \Big|~\sqrt{~~~} \\\\
\sqrt{\tan^2x} =  \sqrt{\frac{1}{3}} \\\\
\tan x = \Big| \frac{1}{ \sqrt{3} } \Big|\\\\
\tan x = \Big| \frac{\sqrt{3}}{ 3 } \Big|\\\\
\tan x =  \frac{\sqrt{3}}{ 3 }~~~\Longrightarrow~~x_1=  \frac{\pi}{6} + k\pi,~~k \in N \\\\  
\tan x =  -\frac{\sqrt{3}}{ 3 }~~~\Longrightarrow~~x_2=  \pi-\frac{\pi}{6} + k\pi = \frac{5\pi}{6} + k\pi,~~k \in N \\\\  




4 0
3 years ago
Read 2 more answers
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