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3 years ago

Glucose is stirred into water to form a solution. In this case, what are the glucose and water?

Chemistry

2 answers:

TEA [102]3 years ago

7 0

Answer: b) The concentrated solution has more solute than the dilute solution.

Explanation:-

Binary Solution is a homogeneous mixture of two components called as solute and solvent.

Solute is the component which is present in smaller proportion and is solid for solid in liquid solution and solvent is the component which is present in larger proportion and is liquid for solid in liquid solution.

Thus as glucose is stirred into water.Glucose is in less amount , it is a solute and water which is in larger amount is called as solvent which together form a solution.

GarryVolchara [31]3 years ago

6 0

Glucose is the solute and water is the solvent.

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An inverted pyramid is being filled with water at a constant rate of 45 cubic centimeters per second. The pyramid, at the top, h

vaieri [72.5K]

Answer:

13.20 cm/s is the rate at which the water level is rising when the water level is 4 cm.

Explanation:

Length of the base = l

Width of the base = w

Height of the pyramid = h

Volume of the pyramid = $V=\frac{1}{3}lwh$

We have:

Rate at which water is filled in cube = $\frac{dV}{dt}= 45 cm^3/s$

Square based pyramid:

l = 6 cm, w = 6 cm, h = 13 cm

Volume of the square based pyramid = V

$V=\frac{1}{3}\times l^2\times h$

$\frac{l}{h}=\frac{6}{13}$

$l=\frac{6h}{13}$

$V=\frac{1}{3}\times (\frac{6h}{13})^2\times h$

$V=\frac{12}{169}h^3$

Differentiating V with respect to dt:

$\frac{dV}{dt}=\frac{d(\frac{12}{169}h^3)}{dt}$

$\frac{dV}{dt}=3\times \frac{12}{169}h^2\times \frac{dh}{dt}$

$45 cm^3/s=3\times \frac{12}{169}h^2\times \frac{dh}{dt}$

$\frac{dh}{dt}=\frac{45 cm^3/s\times 169}{3\times 12\times h^2}$

Putting, h = 4 cm

$\frac{dh}{dt}=\frac{45 cm^3/s\times 169}{3\times 12\times (4 cm)^2}$

$=13.20 cm/s$

13.20 cm/s is the rate at which the water level is rising when the water level is 4 cm.

3 0

3 years ago

2 - Slimotosis

lakkis [162]

Initial observation is a nasty slime and a horrible odor.

4 0

3 years ago

in a reaction 2.5g of sodium sulphate reacted with 4.5g of barium chloride. the products are 3.5g of barium sulphate and the res

klio [65]

The mass of sodium chloride : 3.5 g

<h3>Further explanation</h3>

Given

Reaction :

2.5g of sodium sulphate + 4.5g of barium chloride ⇒ 3.5g of barium sulphate + sodium chloride

Required

The mass of sodium chloride

Solution

Conservation of mass applies to a closed system, <em>where the masses before and after the reaction are the same</em>

From the reaction :

mass of reactants = 2.5 g + 4.5 g = 7.0 g

mass of products = 3.5 g + mass of sodium chloride

mass of reactants = mass of products

7.0 g = 3.5 g + mass of sodium chloride

mass of sodium chloride = 7 g - 3.5 g =3.5 g

3 0

3 years ago

Determine the molar solubility of agi in pure water. ksp (agi) = 8.51 × 10-17.

Alex787 [66]

When the salt AgI dissolves in water it dissociates as follows;
AgI ---> Ag⁺ + I⁻
molar solubility is the number of moles that are dissolved in 1 L of solution.
If molar solubility of AgI is x, then molar solubility of Ag⁺ is x and I⁻ is x.
the formula for solubility product constant - ksp of AgI is given below
ksp = [Ag⁺][I⁻]
ksp = (x)(x)
ksp = 8.51 x 10⁻¹⁷
therefore,
x² = 8.51 x 10⁻¹⁷
x = 9.22 x 10⁻⁹
since molar solubility of AgI is x, then molar solubility of AgI is 9.22 x 10⁻⁹ M

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3 years ago

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Virty [35]

Answer:

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Explanation:

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