I believe it's a proportion of volume over temperature = volume and temperature. cross multiply and divide and see what u get. if it looks right go fro it if not try something else. I hope this helps!
Answer:
Explained below.
Explanation:
First of all, the orbital path of electron is mostly parabolic in electric field.
In an electric field, electrons behave very similar to a projectile. Thus, Electrons have a parabolic path in an electric field simply because the speed of the electrons in a direction which is perpendicular to the electric field is constant since there is no force. Therefore, there will be no acceleration along that perpendicular direction. However there will be an acceleration that is constant in the direction of the electric field which makes it act in a similar manner to a projectile under gravity.
Answer:
The work done by the gas expansion is 5875 J,
Since the work done is positive, the work is done by the gas on the surroundings.
Explanation:
Given;
change in internal energy, ΔU = -4750 J
heat transferred to the system, Q = 1125 J
The change in internal energy is given by;
ΔU = Q - W
Where;
W is the work done by the system
The work done by the system is calculated as;
W = Q - ΔU
W = 1125 - (-4750)
W = 1125 + 4750
W = 5875 J
Since the work done is positive, the work is done by the gas on the surroundings (energy flows from the gas to the surroundings).
Therefore, the work done by the gas expansion is 5875 J
Compounds often differ from elements.
Answer:
Li⁺
Explanation:
In ion formation, the ionization energy plays a very important role. To form an ion, an atom will lose or gain an electron to become charged.
The higher the ionization energy of an atom, the more the energy required to remove an electron from it to form an ion.
- Ionization energy is the energy required to remove an electron from an atom.
- It is the readiness of an atom to lose an electron. The lower the value, the easier it is for an atom to lose an electron and vice versa.
Generally, down the group, ionization energy decreases. Since both potassium and lithium are in group 1, Li will have a higher ionization energy. It will take more energy to form Li⁺ compared to K⁺.
