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Roman55 [17]
3 years ago
7

Please help IM IN HURRY!!!

Chemistry
1 answer:
Vladimir [108]3 years ago
3 0
1.9000 kilogram/cubic meter
8400 kilogram/cubic meter
19300 kilogram/cubic meter
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What are the chemical properties of acids​
Oliga [24]

Answer:

Acids are sour in taste. Acids react with carbonates and hydrogen carbonates to form a salt, water, and carbon dioxide gas. Extremely active metals such as Potassium (K), Calcium (Ca), Sodium (Na), etc tend to explode when combined with acids. Weak Acids like Carbonic Acid doesn't act with any metal at all.

I copied and pasted

but I hope the info helps

7 0
3 years ago
4. A total of 226 J of heat are absorbed as 58.3 g of lead is heated from 12.0oC to 42.0oC. From this data, what is the specific
Zanzabum
C = Q / M * ΔT

Δf - Δi = 42.0ºC - 12.0ºC = 30.0ºC

C =  226 J / 58.3 * 30.0

C = 226 / 1749

C = 0.129 J/gºC

hope this helps!

6 0
3 years ago
The advantage of a fixed pulley on a flag pole is that it______.
Finger [1]
Your answer would be A for your homework
6 0
3 years ago
Explain how you know it must be oxygen. Where
kaheart [24]

Answer:

oxygen is a present in our atmosphere and mixed with other gases on the surrounding screen plants are also measure source of getting oxygen they take carbon dioxide from making their food by for the cities and give away oxygen in return

Explanation:

most of the earth oxygen comes from tiny Ocean plants are called phytoplaston

4 0
2 years ago
Butane C4H10 (g),(Hf = –125.7), combusts in the presence of oxygen to form CO2 (g) (Delta.Hf = –393.5 kJ/mol), and H2O(g) (Delta
shusha [124]

Answer: The enthalpy of combustion, per mole, of butane is -2657.4 kJ

Explanation:

The balanced chemical reaction is,

2C_4H_{10}(g)+13O_2(g)\rightarrow 8CO_2(g)+10H_2O(g)

The expression for enthalpy change is,

\Delta H=[n\times H_f_{products}]-[n\times H_f_{reactants}]

Putting the values we get :

\Delta H=[8\times H_f_{CO_2}+10\times H_f_{H_2O}]-[2\times H_f_{C_4H_{10}+13\times H_f_{O_2}}]

\Delta H=[(8\times -393.5)+(10\times -241.82)]-[(2\times -125.7)+(13\times 0)]

\Delta H=-5314.8kJ

2 moles of butane releases heat = 5314.8 kJ

1 mole of butane release heat = \frac{5314.8}{2}\times 1=2657.4kJ

Thus enthalpy of combustion per mole of butane is -2657.4 kJ

3 0
3 years ago
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