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3 years ago

7

Please help IM IN HURRY!!!

1 answer:

Vladimir [108]3 years ago

3 0

1.9000 kilogram/cubic meter
8400 kilogram/cubic meter
19300 kilogram/cubic meter

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The atomic number of nitrogen is 7. The mass is 14.01. This means that a) All nitrogen atoms have exactly 7 neutrons b) A small

adelina 88 [10]

This means that there are 7 protons in the nucleus of a nitrogen atom.

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3 years ago

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When is the potential energy between two atoms at zero?

ExtremeBDS [4]

Answer:

When two atoms are very far apart, the potential energy approaches zero.

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3 years ago

The coordination compound Co3[Cr(CN)6]2 contains Co2+ cations and a complex anion. What is the likely oxidation state for Cr in

otez555 [7]

Answer:

-3

Explanation:

The oxidation state or oxidation number of an atom is the total number of electrons that an atom either gains or loses in order to form a chemical bond with another atom.

The complex anion here is [Cr(CN)6]3-.

Now, as the oxidation state of CN or cyanide ligand is -1, and if we suppose the oxidation state of Cr to be 'x', then; x - 6 = -3 (overall charge on the anion),

so x= +3. Hence the oxidation state of Chromium in this complex hexacyanochromium (III) anion comes out to be -3.

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3 years ago

Draw the partial (valence-level) orbital diagram, and write the symbol, group number, and period number of the element:

Lapatulllka [165]

Answer:

a) The element is Manganese (Mn)

b) The element is Zirconium (Zr)

Explanation:

The step by step analysis and explanation is as shown in the attachment

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3 years ago

Molecules have ionization energies, just like atoms do. The ionization energy for molecular oxygen, for example, is 1314 kJ/mol.

taurus [48]

Answer:

91.1835 nm

Explanation:

Given that the ionization energy of the oxygen molecule = 1314 kJ/mol

It means that

1 mole of oxygen molecules can be ionized by the energy = 1314 kJ = 1314000 J

1 mole of molecules contains 6.022 × 10²³ atoms

So,

6.022 × 10²³ atoms of oxygen molecules can be ionized by the energy = 1314000 J

1 atom require $\frac{1314000}{6.022\times 10^{23}}\ J$ of energy

Energy = $2.18\times 10^{-18}\ J$

Also

$E=\frac {h\times c}{\lambda}$

Where,

h is Plank's constant having value $6.626\times 10^{-34}\ Js$

c is the speed of light having value $3\times 10^8\ m/s$

$\lambda$ is the wavelength

So,

$\lambda=\frac {h\times c}{E}$

$\lambda=\frac{6.626\times 10^{-34}\times 3\times 10^8}{2.18\times 10^{-18}}\ m$

$\lambda=91.1835\times 10^{-9}}\ m$

Also,

$1\ nm=10^{-9}}\ m$

So, wavelength = 91.1835 nm

6 0

3 years ago