This means Square root (^1/2). this is kind of hard to read. anyways. 32^(1/2) separates into 4^(1/2) and 8^(1/2), which further separates into 4^(1/2) and 2^(1/2), root 4 becomes 2, their are two root 4's, so you get 2 x 2, and you are left with 2^(1/2) now why go to all this trouble. because now you can multiply the 4 you created (2x2) times, the 7... giving you 28*2^(1/2) now subtract it from the the other one with root 2. -5*2^(1/2), giving you 23*2^(1/2)-...idk what that last bit is. if its a odd number then this is the end of the problem, if you can get it to root 2. then do that and simplify.
Answer:
the average of this new list of numbers is 94
Step-by-step explanation:
Hello!
To answer this question we will assign a letter to each number for the first list and the second list of numbers, remembering that the last number of the first list is 80 and the last number of the second list is 96
for the first list
for the new list
To solve this problem consider the following
1.X is the average value of the second list
2. We will assign a Y value to the sum of the numbers a, b, c.
a + b + c = Y to create two new equations
for the first list
solving for Y
Y=(90)(4)-80=280
Y=280=a+b+c
for the second list
the average of this new list of numbers is 94
Answer:
b
Step-by-step explanation:
there you go dude i did the math for you :)
Answer:
Step-by-step explanation:
The common denominator of both fractions is 8. Therefore,, divide the denominator of each fraction, then multiply what you get by the numerator of each fraction.
Thus:
The answer is (-6, 5) for K.
In order to find this, we must first note that to find a midpoint we need to take the average of the endpoints. To do this we add them together and then divide by 2. So, using that, we can write a formula and solve for each part of the k coordinates. We'll start with just x values.
(Kx + Lx)/2 = Mx
(Kx + 8)/2 = 1
Kx + 8 = 2
Kx = -6
And now we do the same thing for y values
(Ky + Ly)/2 = My
(Ky + -7)/2 = -1
Ky + -7 = -2
Ky = 5
This gives us the final point of (-6, 5)
