Question

What is the molarity of a solution prepared by dissolving 10.0 grams of NaOH in enough water to make a solution with a total volume of 2.40 liters?
O0.104 M NaOH
O0.201 M NaOH
O0.361 M NaOH
O0.412 M NaOH

Answer 1

Solution :

Molecular mass of NaOH is 23 g/mol .

So, number of moles of NaOH is given by :

$n = \dfrac{10}{40}\ mole$

Now, we know molarity is given by :

$Molarity = \dfrac{Number \ of \ moles\ of \ salute}{Volume ( in \ Liter ) }$

$M = \dfrac{10}{40\times 2.4} \ M\\\\M = 0.104 \ M$

Hence, this is the required solution.