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exis [7]
3 years ago
6

1. How does the period (row) in which an element is located relate to the number of shells that contain electrons?

Chemistry
1 answer:
Kamila [148]3 years ago
4 0

1. The period number tells us about the number of shells in an element(for example Na located in third period has three electron shells)

2. Group number tells us the amount of electrons present in the valence shell thus also tells us about the ionic charges they form

3. They all have a stable electronic configuration with complete valence shells hence they also don't form ions.

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The potential in an electrochemical cell, E, is related to the Gibb's free energy change (ΔG) for the overall cell redox reactio
Nana76 [90]

Answer:

Explanation:

As an example, the following cell reaction: Zn(s) + Cu2+(aq) → Zn2+(aq) + Cu(m) generates a cell voltage of +1.10 V under standard conditions. Calculate and enter delta G degree (with 3 sig figs) for this reaction in kJ/mol.

Zn(s) + Cu2+(aq) → Zn2+(aq) + Cu(m)

ΔG = ΔG° + RTInQ

Q = 1

ΔG = ΔG°

ΔG = =nFE°

n=no of electrons transfered.

E° = 1.1v

ΔG° = -2 * 96500 * 1.10

= -212300J

ΔG° =-212.3kJ/mol

<h3>Therefore, the ΔG° = -212.3kJ/mol</h3>
5 0
3 years ago
The half-reaction occurring at the cathode in the balanced reaction shown below is __________?2Ag(s) + 1/2 O2(g) + 2H+(aq) → 2Ag
Shtirlitz [24]

Answer:

Correct choice are C and D (they are both, the same).

Explanation:

Cathode is the positive(+) electrode where a reduction occurs.

Reduction is the chemical reaction where the oxidation state is reduced.

2Ag(s) + 1/2 O2(g) + 2H+(aq) → 2Ag+(aq) + H2O (l)

A. 2H2O (l) → O2 (g) + 4H+ (aq) + 4e-

B. 2Ag (s) → 2Ag+ (aq) + 2e-

C. 1/2 O2 (g) + 2H+ (aq) + 2e- → H2O (l)

D. 1/2 O2 (g) + 2H+ (aq) + 2e- → H2O (l)

C or D, are ok. They are the same equation.

Oxygen from ground state reduce the oxidation state from 0 to -2

3 0
3 years ago
What mass of Na2SO4 is needed to make 2.5L of 2.0M solution? (Na=23g; S=32g; O=16g)
zaharov [31]
The molar mass of Na₂SO₄ - 
2 x Na - 2 x23 = 46
1 x S - 1 x 32 = 32 
4 x O - 4 x 16 = 64 
total = 46 + 32 + 64 = 142 g/mol
the molarity of solution - 2.0 M 
in 1 L of solution , 2.0 moles
Therefore in 2.5 L - 2 mol/L x 2.5 L = 5 mol
then the mass of Na₂SO₄ required = 142 g/mol x 5 mol = 710 g
8 0
3 years ago
Read 2 more answers
What is the wavelength of this radiation in centimeters?
Allushta [10]
multiply by 100.4.36×10-5cm
4 0
2 years ago
What mass of oxygen would form from 2.30 moles of water?
Serggg [28]

Answer : The mass of oxygen will be, 36.8 grams

Solution : Given,

Moles of water = 2.30 moles

Molar mass of O_2 = 32 g/mole

First we have to calculate the moles of oxygen.

The balanced chemical reaction will be,

2H_2O\rightarrow 2H_2+O_2

From the balanced reaction we conclude that

2 moles of water decomposes to give 1 mole of O_2

2.30 moles of water decomposes to give \frac{2.3}{2}=1.15 moles of O_2

Now we have to calculate the mass of oxygen.

\text{Mass of }O_2=\text{Moles of }O_2\times \text{Molar mass of }O_2

\text{Mass of }O_2=(1.15moles)\times (32g/mole)=36.8g

Therefore, the mass of oxygen will be, 36.8 grams

8 0
3 years ago
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