How do you know that individual 1 is heterozygous for the trait
1 answer:
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Answer:
The correct answer would be 48 percent.
It can be solved by using the Hardy-Weinberg equation.
p² + 2pq+ q² = 1
p + q = 1
where, p² represents homozygous dominant's frequency that is, SS in this case,
q² represents homozygous recessive's frequency that is, ss in this case,
2pq represents heterozygous dominant's frequency that is, Ss in this case.
p represents dominant allele's frequency and q represents the recessive allele's frequency.
Now, the percentage of homozygous recessive or short stems is 35%. Therefore, the frequency of homozygous recessive would be 0.35.
Thus, the value of q² = 0.35
So, q = = 0.59 which is approximately equals to 0.6.
As p + q = 1 so, q = 1 - 0.6 = 0.4
The frequency of heterozygous (Ss) = 2pq = 2(0.6)(0.4) = 0.48
Hence, the frequency of heterozygous would be 48 percent.
Answer:
The correct answer is option D. "lipid".
Explanation:
Lipids, known also as fats or oils, are organic compounds that are insoluble in water and are made up of carbon, hydrogen, and oxygen. The formula of this question shows a biomolecule that is made up of this three atoms, and even though carbohydrate are made up of this three atoms as well, we can determine that it belongs to a lipid because it contains many more hydrogen atoms than oxygen atoms. Other characteristic of lipids is their long chains of carbon and hydrogen atoms, which are represented by the lines shown in blue. I attached the missing formula.
