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Lisa [10]
3 years ago
5

In parallelogram ABCD above, AE =2x+4 and AC=6x. What is the length of CE?

Mathematics
1 answer:
lawyer [7]3 years ago
4 0

Answer:

4-4x

Step-by-step explanation:

From the parallelogram

CE = CA+AE

Since CA = -AC

CE = -AC+AE

GIVEN

AC = 6x

AE= 2x+4

Substitute

CE = -6x+2x+4.

CE = -4x+4

Gene the length of CE is 4-4x

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What are the solutions of the equation x4 – 9x2 + 8 = 0? Use u substitution to solve.
rosijanka [135]

Answer:

Option (2)

Step-by-step explanation:

Given equation is,

x⁴- 9x² + 8 = 0

Let x² = t

By substituting the value of x²= t in the equation,

t² - 9t + 8 = 0

t² - 8t - t + 8 = 0

t(t - 8) - 1(t - 8) = 0

(t - 1)(t - 8) = 0

(t - 1) = 0 ⇒ t = 1

(t - 8) = 0 ⇒ t = 8

Since, t = x²

x² = 1 ⇒ x = ±1

x² = 8 ⇒ x = ±2√2

Therefore, Option (2) will be the correct option.

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3 years ago
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Answer:

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8. A store owner paid $15 for a book. She marked up the price of the book by 40% to determine its selling price. What is the sel
alexdok [17]

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Step-by-step explanation:

5 0
3 years ago
A running circuit is in the shape of a triangle with lengths of 6km, 6.5km and 7km. What are the sizes of the angles (in minutes
Rudik [331]

A <u>triangle</u> is an example of a class of <em>figures</em> referred to as <em>plane shapes</em>. It has <u>three</u> straight <u>sides</u> and <u>three</u> internal <u>angles</u> which sum up to 180^{o}. The <em>measures</em> of the internal <u>angles</u> of the <u>triangle</u> given in the question are A = 52.6^{o}, B = 59.4^{o}, and C = 68^{o}.

A <u>triangle</u> is an example of a class of <em>figures</em> referred to as <em>plane shapes</em>. It has <u>three</u> straight <u>sides</u> and <u>three</u> internal <u>angles</u> which sum up to 180^{o}.

Considering the given question, let the <u>sides</u> of the triangle be: a = 6 km, b = 6.5 km, and c = 7 km.

Apply the <em>Cosine rule</em> to have:

c^{2} = a^{2} + b^{2} - 2ab Cos C

So that;

7^{2} = 6^{2} + (6.5)^{2} - 2(6 * 6.5) Cos C

49 = 36 + 42.25 - 78Cos C

78 Cos C = 78.25 - 49

               = 29.25

Cos C = \frac{29.25}{78}

         = 0.375

C = Cos^{-1} 0.375

   = 67.9757

C = 68^{o}

Apply the <em>Sine rule</em> to determine the <u>value</u> of B,

\frac{b}{Sin B} = \frac{c}{Sin C}

\frac{6.5}{Sin B} = \frac{7}{Sin 68}

SIn B = \frac{6.5 *Sin 68}{7}

         = 0.861

B = Sin^{-1} 0.861

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B = 59.4^{o}

Thus to determine the value of A, we have;

A + B + C = 180^{o}

A + 59.4^{o} + 68^{o} = 180^{o}

A = 180^{o} - 127.4

  = 52.6

A = 52.6^{o}

Therefore the <u>sizes</u> of the <em>internal angles</em> of the triangle are: A = 52.6^{o}, B = 59.4^{o}, and C = 68^{o}.

For more clarifications on applications of the Sine and Cosine rules, visit: brainly.com/question/14660814

#SPJ1

8 0
2 years ago
Rewrite the equation by completing the square. 4 x^{2} +8 x +3 = 0<br>solve equation in (x+__)^2=__
sergiy2304 [10]

Answer:

4(x+1)^2-1

Step-by-step explanation:

use b/2^2 in order to create a new term to completed the square

hope this helps ''whole lotta love'' NUNU

8 0
3 years ago
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