The presence of a membrane bound nucleus describes the evolution of eukaryotes from prokaryotic organisms. The endosymbiotic theory describes the same, the large cells engulfed the smaller ones, and the engulfed cells were not digested but started living in mutual cooperation with the engulfing cell. Mitochondria and chloroplast are thought to be the engulfed cell
Answer:
1. Allele frequency of b = 0.09 (or 9%)
2. Allele frequency of B = 0.91 (0.91%)
3. Genotype frequency of BB = 0.8281 (or 82.81%)
4. Genotype frequency of Bb = 0.1638 (or 16.38%)
Explanation:
Given that:
p = the frequency of the dominant allele (represented here by B) = 0.91
q = the frequency of the recessive allele (represented here by b) = 0.09
For a population in genetic equilibrium:
p + q = 1.0 (The sum of the frequencies of both alleles is 100%.)
(p + q)^2 = 1
Therefore:
p^2 + 2pq + q^2 = 1
in which:
p^2 = frequency of BB (homozygous dominant)
2pq = frequency of Bb (heterozygous)
q^2 = frequency of bb (homozygous recessive)
p^2 = 0.91^2 = 0.8281
2pq = 2(0.91)(0.9) = 0.1638
1. Meiosis : During prophase of meiosis I, crossing over occurs which results in intermixing of genes between parent.
2. 25 %. In monohybrid cross, offspring produced in phenotypic ratio 3:1. ( 4 offspring, each have 25 % )
3. 75 %. In monohybrid cross, offspring produced in phenotypic ratio 3:1. 3 (75 %) with dominant trait and 1 (25%) with recessive trait.
4. 100%. In incomplete dominance all the offspring produced in F1 generation is neither dominant nor recessive. in this case all offspring will be pink.
5. Tt. Both the alleles T and t will segregate independently.
6. aabb. it will be the rarest combination.
7. 56%. 9 out of 16 seeds produced in the ratio 9:3:3:1 will be round and yellow.