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3 years ago

PLZ ANSWER ASAP WILL MAKE BRAINLIEST FOR BEST ANSWER AND EXPLAIN YOUR ANSWER

Mathematics

1 answer:

r-ruslan [8.4K]3 years ago

6 0

Lmâo your all on your own with this one

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I need some help, please help. I have been stuck on this for days.

dlinn [17]

Answer:

Angle CDE equals 155 degrees :D

Step-by-step explanation:

parallel lines

since the left angle is 57, angle BAE is also 57

180-57=123

right angle=90

115+90+123+57=385

540-385=155

thus, angle CDE equals 155 degrees

5 0

2 years ago

Read 2 more answers

Simplify the expression using order of operation 5 x 2 + 3 to the power of 2

TiliK225 [7]

answer= 1

5 x 2 - 3^2

1. First simplify exponents

= that is nine

2. Then Do 5 x 2- 9

5 x 2=10

10-9

= 1

6 0

3 years ago

A Dodecahedron (12 sided die) is thrown, what is the P( odd OR a number greater than 6)?

djverab [1.8K]

Answer:

6 numbers greater than 6, plus 1,3 and 5- so nine total.

9/12, simplified 3/4

3 0

3 years ago

A football stadium sells regular and box seating. There are twelve times as many

Vera_Pavlovna [14]

Answer:

There are 801 box seats and 9612 regular seats.

explanation:

Let the number of box seats be x,

Then the regular seats is 12x

The sum of seats equals to 10,413

Solve:

12x + x ➙ 10,413

13x ➙ 10413

x ➙ 801

There are 801 box seats.

Find for regular seats:

➙ 12(x)

➙ 12(801)

➙ 9612

There are 9612 regular seats.

6 0

2 years ago

Read 2 more answers

In order to estimate the average time spent on the computer terminals per student at a local university, data were collected for

Setler [38]

Answer:

7) d)

standard error of the mean of one sample of 'n' observation = 0.20

8) a)

The margin of Error = 0.392

9) d

The 95% of confidence intervals are (8.61 , 9.39)

Step-by-step explanation:

solution:-

The Given data sample size 'n' = 81

Given Population standard deviation 'σ' = 1.8 hours

The standard error of the mean of one sample of 'n' observation is

Standard error (SE)

= $\frac{S.D}{\sqrt{n} }$

= σ / √n

= $\frac{1.8}{\sqrt{81} } =0.2$

standard error of the mean of one sample of 'n' observation = 0.20

Solution:-

The Given data sample size 'n' = 81

Given Population standard deviation 'σ' = 1.8 hours

Given the probability is 0.95

The z- score = 1.96 at 0.05 level of significance.

The margin of Error = $\frac{z_{0.95} S.D}{\sqrt{n} }$

= $\frac{1.96 (S.D)}{\sqrt{n} }$

= $\frac{1.96 (1.8)}{\sqrt{81} }$

= 0.392

The margin of Error = 0.392

Solution:-

The 95% of confidence intervals are

$(x^{-} - 1.96\frac{S.D}{\sqrt{n} } , x^{-} + 1.96\frac{S.D}{\sqrt{n} } )$

$(9 - 1.96\frac{1.8}{\sqrt{81} } , 9+ 1.96\frac{1.8}{\sqrt{81} } )$

(9 - 0.392 , (9 + 0.392)

(8.609 , 9.392)

The 95% of confidence intervals are (8.61 , 9.39)

4 0

3 years ago