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kolbaska11 [484]
4 years ago
9

(Please Help) A small city conducts a survey to determine how its residents feel about building a public pool facility. Research

ers go door-to-door one day from 9:00 a.m. to 5:00 p.m. to ask if the adult resident would like to complete the survey. What kind of sampling technique is being used? Against which group would the survey most likely be biased?
A. Systematic sampling; the sample would be biased against adults who are unemployed.
B. Volunteer sampling; the sample would be biased towards those who complete the survey.
C. Simple random sampling; the sample would be unbiased.
D. Convenience sampling; the sample would be biased against adults who work during the day.
Mathematics
2 answers:
alekssr [168]4 years ago
5 0

Answer:

D- convenience sampling, the sample would be biased against adults who work during the day

Step-by-step explanation:


sergejj [24]4 years ago
4 0

Answer:

D. Convenience sampling; the sample would be biased against adults who work during the day.

Step-by-step explanation:

Many adults work a typical 9-5 job, therefore if the survey goes on during their full shift, none of them will get to answer. Most people who answer the survey will either be unemployed, or work at night, and no adult with a day job will get to voice their opinion.

please mark brainliest

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Answer:

See explanation below.

Step-by-step explanation:

We assume that the data is given by :

x: 30, 30, 30, 50, 50, 50, 70,70, 70,90,90,90

y: 38, 43, 29, 32, 26, 33, 19, 27, 23, 14, 19, 21.

Where X represent the cost for scholarships in thousands of dollars and y represent the cost of life for an academic semester (The data comes from the web)

We can find the least-squares line appropriate for this data.  

For this case we need to calculate the slope with the following formula:

m=\frac{S_{xy}}{S_{xx}}

Where:

S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i)}{n}

S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}

So we can find the sums like this:

\sum_{i=1}^n x_i = 30+30+30+50+50+50+70+70+70+90+90+90=720

\sum_{i=1}^n y_i =38+43+29+32+26+33+19+27+23+14+19+21=324

\sum_{i=1}^n x^2_i =30^2+30^2+30^2+50^2+50^2+50^2+70^2+70^2+70^2+90^2+90^2+90^2=49200

\sum_{i=1}^n y^2_i =38^2+43^2+29^2+32^2+26^2+33^2+19^2+27^2+23^2+14^2+19^2+21^2=9540

\sum_{i=1}^n x_i y_i =30*38+30*43+30*29+50*32+50*26+50*33+70*19+70*27+70*23+90*14+90*19+90*21=17540

With these we can find the sums:

S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}=49200-\frac{720^2}{12}=6000

S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i)}=17540-\frac{720*324}{12}{12}=-1900

And the slope would be:

m=-\frac{1900}{6000}=-0.317

Nowe we can find the means for x and y like this:

\bar x= \frac{\sum x_i}{n}=\frac{720}{12}=60

\bar y= \frac{\sum y_i}{n}=\frac{324}{12}=27

And we can find the intercept using this:

b=\bar y -m \bar x=27-(-0.317*60)=46.02

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y=-0.317 x +46.02

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Answer:

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Step-by-step explanation:

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