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DIA [1.3K]
3 years ago
12

Which equation describes the function? Will give brainliest

Mathematics
1 answer:
Natalija [7]3 years ago
4 0

Answer:

y = - \frac{7}{3} x  + 4

Step-by-step explanation:

I'm going to use the process of elimination to get rid of the equations. The equation for slope is y=mx+b with b being the y-intercept. As you can see the y-intercept in this graph is 4 which removes the third equation as a possible answer. The slope is moving from left to right in a downwards direction which means it is a negative slope. The only answer with a negative slope is b therfore it is your answer.

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Write two expressions where the solution is 41.
ladessa [460]

One expression could be.... Nine times 4 plus five equals forty one. ALSO...  Eight times eight equals sixty four then subtract twenty four equals forty one
8 0
3 years ago
You deposit $400 into an account that pays 2% annual interest compounded quarterly.
Ad libitum [116K]
Part A
The exponential model that describes the situation
The formula is
Y (x)=400 (1+0.02/4)^4x
Y (x)=400 (1+0.005)^4x
Y (x)=400 (1.005)^4x
Where x is the number of years

Part B
The value of the account after 5 years
Y (5)=400×(1.005)^(4×5)
Y (5)=441.96

3 0
3 years ago
Read 2 more answers
Part B
Elza [17]

Answer:

copy and paste

Step-by-step explanation:

6 0
3 years ago
We have seen how to convert specified odds from a "fair bet" into the gamblerâs belief about the likelihood of an event happenin
Brut [27]
I had the same question on my hw and I picked c \(“-)/
4 0
3 years ago
PLEASE NEEED HEELPP
krok68 [10]
There are many systems of equation that will satisfy the requirement for Part A.
an example is y≤(1/4)x-3 and y≥(-1/2)x-6
y≥(-1/2)x-6 goes through the point (0,-6) and (-2, -5), the shaded area is above the line. all the points fall in the shaded area, but
y≤(1/4)x-3 goes through the points (0,-3) and (4,-2), the shaded area is below the line, only A and E are in the shaded area. 
only A and E satisfy both inequality, in the overlapping shaded area.

 
Part B. to verify, put the coordinates of A (-3,-4) and E(5,-4) in both inequalities to see if they will make the inequalities true. 
 for y≤(1/4)x-3: -4≤(1/4)(-3)-3
-4≤-3&3/4 This is valid.
For y≥(-1/2)x-6: -4≥(-1/2)(-3)-6
-4≥-4&1/3 this is valid as well. So Yes, A satisfies both inequalities. 
Do the same for point E (5,-4)

Part C: the line y<-2x+4 is a dotted line going through (0,4) and (-2,0)
the shaded area is below the line
farms A, B, and D are in this shaded area. 
8 0
3 years ago
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