Given:
The functions are:


To find:
The function
.
Solution:
We have,


We know that,

On substituting the values of given functions, we get



Therefore, the required function is
.
i guess we'll never know *dance montage*
2*10^6 + 6*10^5 + 3*10^3 +9*10^1 +4*10^0
see expanded form is adding the digits together. and it would be what ever one number is times 10 to the power of how many digits are after that number. you skip the 0's though. hope this helps
Answer:
10
Step-by-step explanation:
3-21-4+32
=-18-4+32
=-22+32
=10