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Ilia_Sergeevich [38]
2 years ago
7

Which number sentence is true?

Mathematics
2 answers:
MArishka [77]2 years ago
8 0

Answer:

Aaaaa

Step-by-step explanation:

sick

nataly862011 [7]2 years ago
6 0
A because -3.3 + 6.1 = 2.8
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50 people plan to attend the dance and each person will eat 2 slices of cake. If each cake contains 20 slices, how many cakes sh
Naya [18.7K]

Answer:

5

Step-by-step explanation:

You <em>multiply</em> the number of people by the number of each slices each person gets. Which is 100; 50x2.

Each cake has 20 slices so you <em>divide</em> 100 by 20. Which equals 5.

It would take 5 cakes to feed all 50 people 2 slices each.

<em>Hope this helps</em>. :)

3 0
3 years ago
What is 12.375 written in expanded form? how is it written with number names
Anettt [7]
Twelve and three hundred seveny-five
7 0
3 years ago
Read 2 more answers
What is the coefficient of the second term of the trinomial?
Schach [20]
This is easy since you are already given the binomials. Just multiply them together.
(3x + 3)(3x + 3)
9x^2 + 9x + 9x + 9
9x^2 + 18x + 9.
The coefficient of term b is 18, so B = 18
6 0
3 years ago
Read 2 more answers
Please help, I’m really confused
Alex17521 [72]

<u>Given</u>:

The given triangle is a right angled triangle.

The length of the hypotenuse is 17 units.

One of the legs of the triangle measure x units.

The one of the angles of the right triangle is 60°

We need to determine the value of x.

<u>Value of x:</u>

The value of x can be determined using the trigonometric ratio.

Thus, we have;

sin \ \theta=\frac{opp}{hyp}

Substituting \theta=60^{\circ}, opp=x and hyp=17 in the above formula, we get;

sin \ 60^{\circ}=\frac{x}{17}

Multiplying both sides of the equation by 17, we get;

sin \ 60^{\circ} \times 17=x

Simplifying, we get;

0.866 \times 17=x

Multiplying, we get;

14.722=x

Rounding off to the nearest tenth, we get;

14.7=x

Thus, the value of x is 14.7

5 0
3 years ago
Use a transformation to solve the equation.    f ∙ 8 = 40 a f=5 b f=32 c f=48 df=320
alekssr [168]
Using Taylor expansion, show that
f0
(x0) = f(x0 + h) − f(x0)
h − h
2
f00(ξ),
for some ξ lying in between x0 and x0 + h.
Solution: We expand the function f in a first order Taylor polynomial around x0:
f(x) = f(x0)+(x − x0)f0
(x0)+(x − x0)
2 f00(ξ)
2 ,
where ξ is between x and x0. Let x = x0 + h:
f(x0 + h) = f(x0) + hf0
(x0) + h2
2 f00(ξ).
Solving for f0
(x0), we obtain:
f0
(x0) = f(x0 + h) − f(x0)
h − h
2
f00(ξ)
4 0
2 years ago
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