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-BARSIC- [3]
3 years ago
10

Can anyone help me out

Mathematics
1 answer:
Talja [164]3 years ago
5 0
Pray to God to show u and everybody here the way of Intelligence
You might be interested in
Plz help on rationalising surds
Fittoniya [83]
(√5 + 3)² / √20=
((√5 + 3)² / √20)(√20/√20)=
(√20(√5 + 3)²) / (√20)²=
√20(5+6√5+9) /20=
√20 (14+6√5) /20=
(14√20 +6√100) /20=
(14√20 +60) / 20=
(14(√4√5) + 60) /20=
(14(2)(√5)+60) / 20=
(28√5+60) /20=
(7√5+15) / 5

Answer:(√5 + 3)² / √20= <span>(7√5+15) / 5</span>
3 0
3 years ago
12. Si R(x)=-5x2+x-2 y S(x)=-x - 3x, se<br>¿cuál es el resultado de R(x) + S(x) ?​
lesya692 [45]

Answer:

El resultado eres: R(x) + S(x) = -6x^2 - 2x - 2

Step-by-step explanation:

Se dan las siguientes funciones

R(x) = -5x^2 + x - 2

S(x) = -x^2 - 3x

Cuál es el resultado de R(x) + S(x) ?​

Se soman los fatores en comun. Entonces:

R(x) + S(x) = -5x^2 + x - 2 + (-x^2 - 3x) = -5x^2 + x - 2 - x^2 - 3x = -5x^2 - x^2 + x - 3x - 2 = -6x^2 - 2x - 2

El resultado eres: R(x) + S(x) = -6x^2 - 2x - 2

4 0
3 years ago
NEED ANSWERS ndndjdbd
Andrews [41]
Still need the answer?
5 0
3 years ago
An ice cream cone has a radius of 4 inches and a height of 9 inches. What is the exact value of the volume of the ice cream cone
Nata [24]
<span>π<span>r^2</span></span><span>h/<span>3
this is a formula if it is a right angle cone
</span></span>π(4)^2 (9)/3
exponent, 4^2 then times by π
<span>after times by (9/3)=
≈150.8

I think, double check and see if right</span>
6 0
3 years ago
For each function, y varies directly with x. Find each constant of variation. Then find the value of y when x=-0.3
Viktor [21]

<u><em>Answer:</em></u>

1- The constant of variation is \frac{10}{3}

2- The constant of variation is \frac{4}{3}

<u><em>Explanation:</em></u>

When two variables are in direct variation, this means that when one of them increases, the other increases and vice versa

<u>A direct variation relation is represented as follows:</u>

y = kx

where k is the constant of variation

Now, to get the constant of variation, all we have to do is substitute with the given x and y variables and solve for k

<u>For the given problems:</u>

<u>1- y = \frac{2}{3}\ when\ x=0.2</u>

<u>Therefore:</u>

y = kx\\\\\frac{2}{3} = 0.2k\\\\ k = \frac{10}{3}

<u>2- y = 4\ when\ x=3</u>

<u>Therefore:</u>

y = kx\\ 4 = 3k\\ k = \frac{4}{3}

Hope this helps :)

5 0
3 years ago
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