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Andru [333]
3 years ago
5

Which inequality is represented by this graph? -5 4 -3 -2 -1 0 1 N 3 4 5

Mathematics
1 answer:
Westkost [7]3 years ago
7 0

Answer:

x≥0

Step-by-step explanation:

The arrow is moving right, to the larger numbers from the starting point at 0. This means that x has to be greater than 0

Because the point at 0 is an empty white dot, it means that it is a 'greater than or equal to' symbol ( looks like this ≤ or ≥, depending on which side you write the x)

So, the final answer is x is greater than or equal to 0, which in maths terms looks like this x≥0, or this 0≤x.

NOTE:

- filled in dot on the number line =  greater than, or less than (>)

- empty dot on number line [like the one on this Q] = greater than or equal to, or less than or equal to (≥)

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A group of students is arranging squares into layers to create a project. The first layer has 6 squares. The second layer has 12
posledela

Answer:

Explicit formula: s_{n}=6(2)^{n-1}

Step-by-step explanation:

Let the number of squares in n^{th} layer be s_{n}

Given:

Number of squares in first layer, s_{1}=6

Number of squares in second layer, s_{2}=12

Therefore, the number of squares increases by a factor of 2.

So, it follows a geometric sequence with the first term as 6 and common ratio of 2.

For a geometric sequence, the n^{th} term with common ratio r is given as:

s_{n}=s_{1}\times r^{n-1}

Here, r=2,s_{1}=6

∴ Explicit formula: s_{n}=6(2)^{n-1}

7 0
3 years ago
A study is planned to compare the proportion of men who dislike anchovies with the proportion of women who dislike anchovies. Th
andrey2020 [161]

Answer:

The requirements are satisifed since we have the proportion estimated, the sample sizes provided, we assume random sampling for the selection of the data and the distribution for the difference of proportions can be considered as normal

z=\frac{0.67-0.84}{\sqrt{0.755(1-0.755)(\frac{1}{41}+\frac{1}{56})}}=-1.923  

Step-by-step explanation:

The requirements are satisifed since we have the proportion estimated, the sample sizes provided, we assume random sampling for the selection of the data and the distribution for the difference of proportions can be considered as normal

Data given and notation  

n_{M}=41 sample of male selected

n_{W}=56 sample of demale selected

p_{M}=0.57 represent the proportion of men who dislike anchovies

p_{WCB}=0.84 represent the proportion of women who dislike anchovies

z would represent the statistic (variable of interest)  

p_v represent the value for the test (variable of interest)

Concepts and formulas to use  

We need to conduct a hypothesis in order to check if the proportion for men is different from women  , the system of hypothesis would be:  

Null hypothesis:p_{M} = p_{W}  

Alternative hypothesis:p_{M} \neq p_{W}  

We need to apply a z test to compare proportions, and the statistic is given by:  

z=\frac{p_{M}-p_{W}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{M}}+\frac{1}{n_{W}})}}   (1)

Where \hat p=\frac{X_{M}+X_{W}}{n_{M}+n_{W}}=\frac{0.67+0.84}{2}=0.755

z-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.  

Calculate the statistic

Replacing in formula (1) the values obtained we got this:  

z=\frac{0.67-0.84}{\sqrt{0.755(1-0.755)(\frac{1}{41}+\frac{1}{56})}}=-1.923  

4 0
4 years ago
A bag contains 3 green marbles and 8 white marbles. Suppose a marble is randomly selected. What are the odds in favor of picking
KatRina [158]
It would be 7 out of 11 because there are 8 marbles and you only took out one white marble

4 0
3 years ago
Read 2 more answers
A school purchsed basketball for $20 each and footballs for $15 each. they a brought a total of 28 for $480 how many of each typ
satela [25.4K]

Answer:

i in total spent : 480

Step-by-step explanation:

he bought 12 basketballs = 240

he bought 16 football = 240

you can decide how to make your system

4 0
3 years ago
Evaluate the limit of lim/n->infinity 6n^2+5/3n^2
castortr0y [4]

we are given

\lim_{n \to \infty} \frac{6n^2+5}{3n^2}

we can see that

degree of numerator = degree of denominator =2

so, we can divide both numerator and denominator by n^2

and we get

\lim_{n \to \infty} \frac{(6n^2+5)/n^2}{(3n^2/n^2)}

\lim_{n \to \infty} \frac{(6n^2/n^2)+(5/n^2)}{(3n^2/n^2)}

now, we can simplify it

\lim_{n \to \infty} \frac{6+(5/n^2)}{3}

now, we can plug n=inf

=  \frac{6+(5/(\infty))}{3}

=  \frac{6+0}{3}

=  \frac{6}{3}

=  2...............Answer

6 0
3 years ago
Read 2 more answers
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