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3 years ago

13

NO LINKS PLEASE; On the calendar, the full moon is shown happening on the eleventh of the month. What moon would you see around

the date shown with the question mark?
First Quarter

New Moon

Waxing Crescent

Waning Gibbous

1 answer:

photoshop1234 [79]3 years ago

3 0

Wanning gibbous

hope it helps u

<em>Plz </em><em>mrk </em><em>me </em><em>brainlest</em>

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A transmission diffraction grating with 420 lines/mm is used to study the light intensity of di event orders (n). A screen is lo

Goshia [24]

Answer:

Explanation:

Diffraction grating is used to form interference pattern of dark and bright band.

Distance between adjacent slits (a ) = 1 / 420 mm

= 2.38 x 10⁻³ mm

2.38 x 10⁻⁶ m

wave length of red light

= 680 x 10⁻⁹ m

For bright red band

position x on the screen

= n λD / a , n = 0,1,2,3 etc

D = distance of screen

putting n = 1 , 2 and 3 , we can get three locations of bright red band.

x₁ = λD / a

= 680 x 10⁻⁹ x 2.8 / 2.38 x 10⁻⁶

= .8 m

= 80 cm

Position of second bright band

= 2 λD / a

= 2 x 80

= 160 cm

Position of third bright band

= 3 λD / a

= 3 x 80

= 240 cm

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3 years ago

What techniques allow us to identify the presence of different elements?

boyakko [2]

Answer:

c

Explanation:

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3 years ago

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A force of 250 N is applied to a hydraulic jack piston that is 0.02 m in diameter. If the piston that supports the load has a di

Vikentia [17]

Answer:

option B

Explanation:

given,

Force exerted by the hydraulic jack piston = F₁ = 250 N

diameter of piston, d₁ = 0.02 m

r₁ = 0.01 m

diameter of second piston, d₂ = 0.15 m

r₂ = 0.075 m

mass of the jack to lift = ?

now,

$\dfrac{F_1}{A_1} =\dfrac{F_2}{A_2}$

$\dfrac{250}{\pi r_1^2} =\dfrac{F_2}{\pi r_2^2}$

$\dfrac{250}{0.01^2} =\dfrac{F_2}{0.075^2}$

$F_2= \dfrac{250}{0.01^2}\times {0.075^2}$

F₂ = 14062.5 N

F = m g

$m = \dfrac{F}{g}$

$m = \dfrac{14062.5}{9.8}$

m = 1435 Kg

hence, the correct answer is option B

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3 years ago

Coulomb's Law: Two identical small charged spheres are a certain distance apart, and each one initially experiences an electrost

Ahat [919]

Answer:

The magnitude of electrostatic force on each charge is quarter of the magnitude of initial electrostatic force. ( ¹/₄ F)

Explanation:

The electrostatic force between two charges is given by Coulomb's law;

$F = \frac{kQ_1Q_2}{r^2}$

where;

Q₁ and Q₂ are the magnitude of the charges

r is the distance between the charges

k is Coulomb's constant

Since the charges are identical;

Q₁ = Q

Q₂ = Q

the electrostatic force experienced by each charge is given by;

$F = \frac{kQ^2}{r^2}$

When each of the spheres has lost half of its initial charge;

Q₁ = Q/2

Q₂ = Q/2

$F_2 = \frac{k(Q/2)(Q/2)}{r^2}\\\\ F_2 = \frac{k(Q)(Q)}{4r^2}\\\\F_2 = \frac{1}{4} (\frac{kQ^2}{r^2} )\\\\F_2 = \frac{1}{4} (F)$

Therefore, the magnitude of electrostatic force on each charge is quarter of the magnitude of initial electrostatic force.

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3 years ago

1.An electrician is deciding what type of material to use for wires. Based on the periodic table, which of the following would b

Alinara [238K]

Without specifics, the best element to conduct electricity would be copper.

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4 years ago